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ch4aika [34]
3 years ago
7

What are short, hairlike structures that help move a cell?

Chemistry
1 answer:
frez [133]3 years ago
7 0

Answer: Cilia

Explanation:

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Aniline is more basic than cyclohexylamine because: (A) electrons on the aniline nitrogen are somewhat delocalized into the arom
Nady [450]

Answer:

The correct answer is A electron on the aniline nitrogen are somehow delocalized to the aromatic ring.

Explanation:

The structure of aniline contain double bonds and lone pair of electron in the nitrogen atom of -NH2 group that is attached to the benzene ring.

  The electron pair present in the nitrogen atom of -NH3 group of aniline undergo delocalization with the aromatic ring of benzene resulting in the formation of resonance hybrid that increases the ability of nitrogen atom of -NH2 group of aniline to easily donate that lone pair of electron.

 ON the other hand the resonance stabilization cannot be possible with the cyclohexylamine ring as it is saturated.

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4 years ago
There are around muscles in the human body<br><br> 640<br> 250<br> 100
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There are 640 muscles in the human body
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4 years ago
What is the molar mass of Au2S
OlgaM077 [116]

Au2S is =<u><em> 426 g/mol</em></u> for molar mass

8 0
4 years ago
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A 2.144-g sample of phosgene, a compound used as a chemical warfare agent during World War I, contains 0.260 g of carbon, 0.347
Greeley [361]
First convert each mass to moles by dividing by the molar mass.

0.347g Oxygen = 0.022 moles
0.260g Carbon = 0.022 moles
1.537g Chlorine = 0.043 moles

Divide each by smallest mole vale (0.022)

Oxygen = 0.022/0.022 = 1
Carbon = 0.022/0.022 = 1
Chlorine = 0.043/0.022 = 2

Therefore the empirical formula is COCl2
4 0
3 years ago
Calculate the number of grams of COOH 3 CH in the vinegar.
IRINA_888 [86]

If you are given the number of moles of sodium bicarbonate, use the balanced chemical equation. The molar mass of the acetic acid is 60 grams per mole. Using stochiometric balance.

 

Number of moles of acetic acid = 3 moles NaHCO3 (1 mol CH3COOH/1 mol NaHCO3) = 3 moles of acetic acid

Grams of acetic acid = 3 moles of CH3COOH (60 g CH3COOH/1 mol CH3COOH) = <span>180 grams of acetic acid</span>

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