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jeka57 [31]
3 years ago
13

One mole of beryllium (be) contains the same number of atoms as 22.99 g of sodium. There are about 2.007×1023 atoms in 9.0 g al.

One mole of calcium (ca) weighs about as much as two moles of neon (ne). 11.495 g of sodium contains 6.022×1023 atoms.
Chemistry
1 answer:
Hoochie [10]3 years ago
4 0

1) the number of atoms (or molecules or ions) in one mole of any substance is same= 6.023 X 10^23

Thus as mass of one mole of sodium = 22.99 grams, this is equal to molar mass of sodium

moles of sodium = mass / molar mass = 22.99/22.99 = 1

Thus number of atoms in Be will be same the number of atoms of 22.99g of sodium

2) The mass of aluminium is given = 9g

atomic mass of Al = 27

Moles of Al =  mass / molar mass = 9/ 27 = 1/3

The atoms of Al in one mole = 6.023 X 10^23

Hence atoms of Al in 1/3 moles of Al = 6.023 X 10^23 / 3 =   2.007 X 10^23

So given statement is true

3) The mass of one mole of Ca = 40grams

The mass of one mole of Neon = 20grams

So yes one mole of Ca will weigh equal to two moles of Ne

4) The atomic mass of sodium = 23 g / mole

Thus 23 grams of sodium contains 6.022×1023 atoms and not  11.495 g of sodium

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Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling
Reil [10]

Answer:

The boiling  point of a 8.5 m solution of Mg3(PO4)2 in water is<u> 394.91 K.</u>

Explanation:

The formula for molal boiling Point elevation is :

\Delta T_{b} = iK_{b}m

\Delta T_{b} = elevation in boiling Point

K_{b} = Boiling point constant( ebullioscopic constant)

m = molality of the solution

<em>i =</em> Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

In solution Mg3(PO4)2 dissociates as follow :

Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

Total ions = 5

<em>i =</em> Van't Hoff Factor = 5

m = 8.5 m

K_{b} = 0.512 °C/m

Insert the values and calculate temperature change:

\Delta T_{b} = iK_{b}m

\Delta T_{b} = 5\times 0.512\times 8.5

\Delta T_{b} = 21.76 K

Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K

\Delta T_{b} = T_{b} - T_{b}_{pure}

T_{b}_{pure} = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

8 0
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Step 1: Given data

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Step 2: Calculate the number of atoms present in 7.2 moles of neon

In order to convert moles to toms, we need a conversion factor. In this case, we will use Avogadro's number: there are 6.02 × 10²³ neon atoms in 1 mole of neon atoms.

7.2 mol × 6.02 × 10²³ atoms/mol = 4.3 × 10²⁴ atoms

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Anaerobic Respiration

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Glucose → lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.  

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Xelga [282]
I’m confused and that comment above is probably a trafficker
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