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Oksana_A [137]
3 years ago
5

Consider the reaction: 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq) this three-step mechanism is proposed: nh3(aq)+ocl−(aq) ⇌k1k2 n

h2cl(aq)+oh−(aq) fast nh2ci(aq)+nh3(aq) ⟶k3 n2h+5(aq)+cl−−(aq) slow n2h+5(aq)+oh−(aq) ⟶k4 n2h4(aq)+h2o(l) fast part a does the mechanism sum to the reaction 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq)?
Chemistry
1 answer:
saw5 [17]3 years ago
6 0

Yes, the mechanism sums to the reaction.

You add the equations, cancelling species that occur on opposite sides of the arrows.

<em>Eq1</em>: NH3(aq) + OCl^(-)(aq) → <u>NH2Cl(aq)</u> + <u>OH^(-)(aq)</u>

<em>Eq2</em>: <u>NH2Cl(aq)</u> + NH3(aq) → <u>N2H5^(+)(aq)</u> + Cl^(-)(aq)

<em>Eq3</em>: <u>N2H5^(+)(aq)</u> + <u>OH^(-)(aq)</u> → N2H4(aq) + H2O(l)

<em>OA</em>: 2NH3(aq) + OCl^(-)(aq) → N2H4(aq) + H2O(l) + Cl^(-)(aq)

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lana [24]
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A metal that does not have much care for its electrons, such as Sodium, Na, is willing to give up its electron more freely. And an atom that really cares about having electrons might be a gas such as chlorine, Cl. The Chlorine atom takes the electron from Sodium, and then the newly formed ions of Na+ and Cl- bond because they have equal and opposite charges and opposites attract. NaCl is formed.

Hydrogen bonds aren’t actually real bonds (I know, the name is deceptive)

Covalent bonds involve the sharing of electrons.

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7 0
2 years ago
2NaOH + H2So4=______+2H2O<br>​
Dmitry [639]

Answer:

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7 0
3 years ago
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fiasKO [112]

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Whereas anions from the list are

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6 0
2 years ago
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lubasha [3.4K]
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Hope this helps!
4 0
3 years ago
What is the concentration of a solution which is 2g in 150cm3 in g/dm3
Irina-Kira [14]

Answer:

13.33 g/dm³

Explanation:

Concentration (g/dm³)= mass(g) ÷ volume (dm³)

Now you need to convert 150 cm³ to dm³

1000cm³ = 1 dm³

thus, 150 cm3= 150 ÷ 1000

= 15dm³

and you already have mass in grams

so concentration  = 2 ÷ 0.15

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8 0
2 years ago
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