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Oksana_A [137]
3 years ago
5

Consider the reaction: 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq) this three-step mechanism is proposed: nh3(aq)+ocl−(aq) ⇌k1k2 n

h2cl(aq)+oh−(aq) fast nh2ci(aq)+nh3(aq) ⟶k3 n2h+5(aq)+cl−−(aq) slow n2h+5(aq)+oh−(aq) ⟶k4 n2h4(aq)+h2o(l) fast part a does the mechanism sum to the reaction 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq)?
Chemistry
1 answer:
saw5 [17]3 years ago
6 0

Yes, the mechanism sums to the reaction.

You add the equations, cancelling species that occur on opposite sides of the arrows.

<em>Eq1</em>: NH3(aq) + OCl^(-)(aq) → <u>NH2Cl(aq)</u> + <u>OH^(-)(aq)</u>

<em>Eq2</em>: <u>NH2Cl(aq)</u> + NH3(aq) → <u>N2H5^(+)(aq)</u> + Cl^(-)(aq)

<em>Eq3</em>: <u>N2H5^(+)(aq)</u> + <u>OH^(-)(aq)</u> → N2H4(aq) + H2O(l)

<em>OA</em>: 2NH3(aq) + OCl^(-)(aq) → N2H4(aq) + H2O(l) + Cl^(-)(aq)

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The balance of the following equations
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A. 6 NaOH   +  2(NH4)3 PO4  ----->  2Na PO4  +  6H2O  +   6NH3

b. C2 H6 O  + 3O2  ---->   2CO2  +  3H2O
5 0
3 years ago
What is the natural rate of nitrogen fixation in Earth’s ecosystems? What is the natural rate of nitrogen fixation in Earth’s ec
quester [9]

Answer:

100 teragrams of nitrogen per year

Explanation:

Nitrogen fixation in Earth's ecosystems is defined as a process where by nitrogen in air is transformed into ammonia or other related nitrogenous compounds. Generally, atmospheric nitrogen is referred to as molecular dinitrogen and it is a nonreactive compound that is metabolically useless to all but a few microorganisms. This process is vital to life due to the fact that inorganic nitrogen compounds are needed for the biosynthesis of amino acids, protein, and all other nitrogen-containing organic compounds. Thus, the natural rate of nitrogen fixation in Earth's ecosystems is 100 tetragrams of nitrogen per year.

7 0
3 years ago
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.3×1015Hz?
Sonja [21]

Answer:

We know that

ħf = ф + Ekmax  

where  

ħ = planks constant = 6.626x10^-34 J s  

f = frequency of incident light = 1.3x10^15 /s (1 Hz =

1/s)

ф = work function of the cesium = 2.14 eV  

Ekmax = max  kinetic energy of the emmitted electron.  

We distinguish that:

1 eV = 1.602x10^-19 J

So:

2.14 eV x (1.602x10^-19 J / 1 eV) = 3.428x10^-19 J

So,

Ekmax = (6.626x10^-34 J s) x (1.3x10^15 / s) - 3.428x10^-19 J

= 8.6138x10^-19 J - 3.428x10^-19 J = 5.1858x10^-19 J  

Answer:

5.19x10^-19 J  

Kinetic energy:

In physics, the kinetic energy of an object is the energy that it owns due to its motion. It is defined as the work required accelerating a body of a given mass from rest to its specified velocity. Having expanded this energy during its acceleration, the body upholds this kinetic energy lest its speed changes.

Answer details:

Subject: Chemistry

Level: College

Keywords:

• Energy  

• Kinetic energy

• Kinetic energy of emitted electrons

Learn more to evaluate:

brainly.com/question/4997492

brainly.com/question/4010464

brainly.com/question/1754173

6 0
3 years ago
Read 2 more answers
Which of the following would contain 48 electrons?
Helga [31]
The answer is cadmium its got 48 electrons which is y its number 48 on the period table
4 0
3 years ago
Is 13.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Andrews [41]
Answer: 
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 E = E^o -0.0592 log Q; in this case E^o is zero. 
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case n = 2 
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 0.023 = -0.0296 { log 0.10 – log [Zn+2] }
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 0.023 = +0.0296 + 0.0296log[Zn+2]
 -0.0066 = 0.0296log[Zn+2]
 -0.22= log[Zn+2]
 [Zn+2] = 10^-0.22 = 0.603 Molar

6 0
3 years ago
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