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Oksana_A [137]
3 years ago
5

Consider the reaction: 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq) this three-step mechanism is proposed: nh3(aq)+ocl−(aq) ⇌k1k2 n

h2cl(aq)+oh−(aq) fast nh2ci(aq)+nh3(aq) ⟶k3 n2h+5(aq)+cl−−(aq) slow n2h+5(aq)+oh−(aq) ⟶k4 n2h4(aq)+h2o(l) fast part a does the mechanism sum to the reaction 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq)?
Chemistry
1 answer:
saw5 [17]3 years ago
6 0

Yes, the mechanism sums to the reaction.

You add the equations, cancelling species that occur on opposite sides of the arrows.

<em>Eq1</em>: NH3(aq) + OCl^(-)(aq) → <u>NH2Cl(aq)</u> + <u>OH^(-)(aq)</u>

<em>Eq2</em>: <u>NH2Cl(aq)</u> + NH3(aq) → <u>N2H5^(+)(aq)</u> + Cl^(-)(aq)

<em>Eq3</em>: <u>N2H5^(+)(aq)</u> + <u>OH^(-)(aq)</u> → N2H4(aq) + H2O(l)

<em>OA</em>: 2NH3(aq) + OCl^(-)(aq) → N2H4(aq) + H2O(l) + Cl^(-)(aq)

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