All categories

3 years ago

Solve : 4+3x =(3x-7)+9.

Mathematics

2 answers:

lesantik [10]3 years ago

6 0

X=3
Hope this helped

dezoksy [38]3 years ago

5 0

Answer:

D.) x = 3

Step-by-step explanation:

4 + 3x = 2(3x - 7) + 9

4 + 3x = 6x - 14 + 9

3x - 6x = 9 - 14 - 4

-3x = -9

x = -(-9)/3

x = 9/3

x = 3

You might be interested in

Kesia knows that 1/4=0.25. Explain how she could use this fact to determine the decimal equivalent of 5/8

STatiana [176]

She knows that
$0.25 = \frac{1}{4} = \frac{2}{8}$
$\frac{5}{8} = \frac{2}{8} + \frac{2}{8} + \frac{1}{8} = \\ 0.25 + 0.25 + \frac{0.25}{2} = \\ 0.25 + 0.25 + 0.125 = 0.625$

4 0

3 years ago

Read 2 more answers

Would like scatter plot image with line of best fit on the plot

dlinn [17]

Just take it in co-ordinate pairs

(x,y)=(Arm span,Height)

Take two points

(58,60)
(41,40)

Slope:-

$\\ \sf\longmapsto m=\dfrac{40-60}{41-58}$

$\\ \sf\longmapsto m=\dfrac{-20}{-17}$

$\\ \sf\longmapsto m=\dfrac{20}{17}$

$\\ \sf\longmapsto m\approx 1.2$

Equation of line in point slope form

$\\ \sf\longmapsto y-y_1=m(x-x_1)$

$\\ \sf\longmapsto y-60=1.2(x-58)$

$\\ \sf\longmapsto y-60=1.2x-69.6$

$\\ \sf\longmapsto 1.2x-y-9.6=0$

Convert to slope intercept form y=mx+b

$\\ \sf\longmapsto y=1.2x-9.6$

Graph attached

7 0

2 years ago

60.3 60.44 witch one is greater

Sindrei [870]

60.44 is greater than 60.3
-you can see this when you subtract 60.3 from 60.44 this would leave a 0.11 which is a positive number.
-thus meaning 60.44 is larger/greater.

4 0

2 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

What is the median of the data set given below? 26, 39, 18, 21, 24, 48, 21, 35

sergiy2304 [10]

To find the Median, place the numbers you are given in value order and find the middle number. <span>If there are two middle numbers, you average them.
</span><span>18, 21, 21, 24, 26, 35, 39, 48

The two middle number are 24 and 26
Average 24 + 26/2 = 25
The median is 25
</span>

6 0

2 years ago

Read 2 more answers