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bekas [8.4K]
3 years ago
13

The length of a rectangle is 6 inches more than its width. If 3 inches are taken from the length and added to the width the figu

re becomes a square with an area of 400 square inches. What are the dimensions of the original figure
Mathematics
1 answer:
NARA [144]3 years ago
3 0

Answer:

The dimensions of a square with area 400 are 20 by 20. This means if 3 inches are taken from the length and added to the width, we get the dimensions were 23 by 17. 23 length 17 widths.

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Solve the following system of equations graphically on the set of axes below. Y=-1/2x +1 and y=x-5
Goshia [24]

Answer:

-1/2x+1=x-5

x=4

y=-4/2+1

y=-2+1

y=-1

(x,y)=(4,-1)

7 0
3 years ago
How to solve it and the formula to solve it
notsponge [240]

i) u + 3 V

1 by 2 + 3 *minus 2

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7 0
3 years ago
The mean length of 10 childrens' index finger is 12.6cm.
ICE Princess25 [194]

Get total lengths by multiplying:

10 x 12.6 = 126

6 x 16.1 = 96.6

Add the total lengths together and divide by 16:

126 + 96.6 = 222.6


222.6 / 16 = 13.9125

Rounded to 2 decimal places = 13.91


answer: 13.91

5 0
1 year ago
What is the answer?<br> 1/4<br> 7/20<br> 5/11<br> 1/2
julsineya [31]

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
the diffrence of two numbers,a and b,is 21,the diffrence of five times a and two times b is 18 what are the values of a and b
Triss [41]

Answer:

a=-8

b=-29

Step-by-step explanation:

Let's assume

first number is a

second number is b

the difference of two numbers,a and b,is 21

so, we get

a-b=21

we can solve for 'a'

a=b+21

the difference of five times a and two times b is 18

so, we get

5a-2b=18

now, we can plug 'a'

5(b+21)-2b=18

now, we can solve for b

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3b+105=18

3b=-87

b=-29

now, we can find 'a'

a=-29+21

a=-8


8 0
3 years ago
Read 2 more answers
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