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Elina [12.6K]
3 years ago
7

It costs Guido $0.20 to send a text message from his cell phone. He has already spent $4 in text messages this month. If he has

a total of $10 that he can spend this month on text messages, write and solve an inequality that will give the greatest number of text messages that he can send. Interpret the solution.
Mathematics
1 answer:
In-s [12.5K]3 years ago
3 0

The greatest number he can spend on is $5 since he has $10 he will have $5 reamining.

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Plz help me ill give brainly
Dafna11 [192]

Answer:

3.6 divided by 3 = 1.2 so 1.2 yards of material can be used on each skirt.

Step-by-step explanation:

4 0
3 years ago
What is 18 2/3-3 5/8
xxTIMURxx [149]

Answer:

=15 1/24

Step-by-step explanation:

18 2/3−3 5/8

=15 1/24

5 0
3 years ago
A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
The temperature was 2.5°C below zero. After 4 hours, the temperature was now 5.6°C
ELEN [110]

Answer:

3.1 degrees celcius

Step-by-step explanation:

5.6C-2.5C=3.1C

5 0
3 years ago
Leicester City Fanstore (LCF) will be selling the "new season jersey" for the 2018-2019 season. The regular price of the jersey
andrew-mc [135]

Complete Question

Leicester City Fanstore (LCF) will be selling the "new season jersey" for the 2018-2019 season. The regular price of the jersey is $80. Each jersey costs $40. Leftover jerseys will be sold at the end of the season (or later) at $30. Since jerseys are produced in China and lead time is long, Puma wants LCF to decide the quantity right now (December 2017).

a. After some analysis using historic data, LCF expects that the demand will follow a Normal distribution with a mean 40,000 and a standard deviation of 8,000 due to uncertainty in team performance. How many jerseys should LCF order?

b. If a customer cannot buy the jersey from LCF (in the case of a stock-out), they may leave the store disappointed and use other channels (such as Puma stores or puma.com) in future. LCF thinks that the lost customer goodwill is around $10. Should LCF change their decision in part (a)? If yes, please state the number of jerseys LCF should order.

c. Please state whether the following statement is always true, and give a brief explanation. If C_o =C_i, the news vendor solution is the mean.

Answer:

a

   N  =  46728

b

  n  =  47728

c

  Yes it is always true  

Step-by-step explanation:

From the question we are told that

   The regular price of the jersey is  P_r = \$ 80

    The cost of producing a jersey is C=  \$ 40

  The left-over price of the jersey is P_o  = $ 30

   The mean is  \mu =  40000

   The standard deviation is \sigma =  8000

   The cost of lost customer goodwill is C_g = \$ 10

Generally the fund that LCF will loss for one jersey if they order for too many  jersey (i.e more than they need )is mathematically represented  

           C_o  =  P_o -  C

=>        C_o  = 40 - 30

=>        C_o  = \$ 10

Generally the fund that LCF will loss for one jersey if they order lesser amount  jersey (i.e less than they need )is mathematically represented  

           C_i  =  P_r -  C

=>        C_i  = 80 - 40

=>        C_i  = \$ 40

Generally the critical ratio is mathematically represented as

             Z  =  \frac{C_i }{ C_i + C_o}

=>           Z =  \frac{40}{ 40 + 10}

=>           Z  = 0.8

Generally the critical value of  Z  = 0.8 to the right of the normal curve is

         z = 0.841

Generally the optimal quantity of jersey to order is mathematically represented as

             N  =  \mu  * [z *  \sigma]

=>          N  =  40000 * [0.841 *   8000]

=>          N  =  46728

Considering question b

  Generally considering the factor of customer goodwill  the fund that LCF will loss for one jersey if they order lesser amount  jersey (i.e less than they need )is mathematically represented  as

           C_k  =  C_i +  C_g

=>        C_k  =  40 +  10

=>        C_k  = \$ 50

Now   the critical ratio is mathematically represented as

             Z  =  \frac{C_k }{ C_k + C_o}

=>           Z =  \frac{50}{ 50 + 10}

=>           Z  = 0.833

Generally the critical value of  Z  = 0.833 to the right of the normal curve is

         z = 0.966

Generally the optimal quantity of jersey to order is mathematically represented as

             n  =  \mu  * [z *  \sigma]

=>          n  =  40000 * [0.966 *   8000]

=>          n  =  47728

Considering question c

    When C_o =C_i then

The critical ratio is mathematically represented as

             Z  =  \frac{C_k }{ C_k + C_k}

=>           Z =  \frac{1}{ 2}

=>           Z  = 0.5          

Generally the critical value of  Z  = 0.5 to the right of the normal curve is

         z = 0

So

The optimal quantity of jersey to order is mathematically represented as

             n  =  \mu  * [z *  \sigma]

=>          n  =  40000 * [0*   8000]

=>          n  =  40000 = \mu

Hence the statement in c is true        

4 0
3 years ago
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