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Bond [772]
2 years ago
7

There are 5,280feet in a mile. Factoid of the day: The longest wedding veil was 63.5 football fields. About how many miles is th

at? Give it ur best guess
Mathematics
1 answer:
Snowcat [4.5K]2 years ago
8 0

Answer:

3 yards and 3,210 feet (I think)

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Can you help me with this problem
alex41 [277]

I think its 8 because 64 divided by 8 is 8.


3 0
3 years ago
I do not remember how to solve this can you help me
monitta
-X+7x-3=0
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4 0
3 years ago
Solve the quadratic equation:<br> 3x^2+x-5=0
adell [148]

3x²+x-5=0

a = 3, b = 1, c= -5

-> ∆ ( delta ) = b²-4ac = 61 > 0

-> x1 =( -b+√∆ )÷ 2a =...

x2 = (-b-√∆)÷2a =...

p/s: do your teachers teach you how to use ∆ ( delta ) in maths calculation ? i live in europe and our teachers teach us that way. however, it is a rịght and fast way. you should learn it.

4 0
2 years ago
3. Given ABCD ≅ FGHJ and mC = 9x - 7, mH = 5x + 13, find the value of x and the measures of angle C and angle H. Show all work
Bas_tet [7]
Since congruence and similarity for polygons is posted in a specific order, we know that angle A=angle F, side A=side F, die B=side G, and so on. Therefore, we have that angle C=angle H = 9x-7=5x+13. Subtracting 5x from both sides to separate the x using the subtraction property of equality, we get 4x-7=13. Next, we can add 7 to both sides to get 4x=20, and divide both sides by 4 to isolate the x and get x=5. Plugging that into angle C or angle H, we get that 9x-7=9*5-7=45-7=38=5*5+13.

Feel free to ask further questions!
5 0
2 years ago
The depth of a lake in Lexington changes over time due to rainfall and evaporation. A few months ago, the depth was 1,300 feet.
SVETLANKA909090 [29]

Answer:

The Depth of the lake had increased by 19%.

Step-by-step explanation:

Given:

Depth of lake few months ago = 1300 ft

depth of lake currently = 1547 ft

We need to find the percent of increase in depth of lake.

Solution:

First we will find the increase in depth of lake.

Increase in depth of lake can be calculated by subtracting Depth of lake few months ago from depth of lake currently.

framing in equation form we get;

increase in depth of lake = 1547-1300= 247\ ft

Now to find the percent of increase in depth of lake we will divide  increase in depth of lake from Depth of lake few months ago and then multiply by 100.

framing in equation form we get;

percent of increase in depth of lake = \frac{247}{1300}\times 100 =  19\%

Hence the Depth of the lake had increased by 19%.

6 0
3 years ago
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