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Gala2k [10]
3 years ago
14

Can anyone help I’ll give you brainliest

Mathematics
2 answers:
inn [45]3 years ago
8 0

Answer:

$3580.50

Annual occurs once a year


elena-s [515]3 years ago
7 0
$80.50 you just multiply them and if you don't have the ability to enter the percent Mark then you don't have to move the decimal

hope this helps
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Elena went to a store where you can scoop your own popcorn and buy as
anygoal [31]

Answers:

c=0.25p

p=4c

c=.25p

c=1/4p

Hope I' not too late -w-'

8 0
3 years ago
What is the value of the expression 6z2+2z+10 when z=3?
grigory [225]

Hi there! Hope this helps, and if it does, please mark brainliest!

Answer:

346

Step-by-step explanation:

6z2+2z+10

(6 x 3)^2 + 2 x 3 + 10

18^2 + 12 + 10

324 + 22

346

5 0
3 years ago
Ken grew 4/5 of an inch last year.sang grew 3/8of an inch.who grew more and by how much
beks73 [17]
Ken grew .425 of an inch more than Sang
7 0
4 years ago
Read 2 more answers
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
What is the volume of a cylinder with base radius 4 and height 5?
Vsevolod [243]

Answer:

251.2 unit²

Step-by-step explanation:

Radius = 4 unit,  height = 5 unit

Volume of cylinder = pi r² h

Where pi(#) = 3.14

Volume = # × 4² × 5

Volume = # × 16 × 5

Volume = 80# unit²

Volume = 80 × 3.14

Volume = 251.2 unit²

I hope this was helpful, please rate as brainliest

5 0
3 years ago
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