Question

Algebra: WORD PROBLRM

Answer 1

$A=Adult$, $C=Child$

$Garcia:2A+3C=44.5$
$Smith:3A+6C=78$

$A= \frac{44.5-3C}{2}$

$3( \frac{44.5-3C}{2})+6c=78$
$66.75-4.5c+6c=78$
$1.5C=11.5$
$C=7.66$

$2A+3(7.66)=44.5$
$2A=21.52$
$A=10.76$

Children's ticket = $7.66
Adult's ticket = $10.76

Sorry it's not as clear as it could be, kinda in a rush