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timama [110]
3 years ago
5

Please help!!! On these questions^^^^ picture is aboveee

Mathematics
1 answer:
jarptica [38.1K]3 years ago
4 0

Answer:

down*

Step-by-step explanation:

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Given the equation y - 4 = (x + 8) in point-slope form, identify the equation of the same line in standard form.
yawa3891 [41]
Standard form
solve for y
y-4=x+8
add 4 to both sides
y=x+12
4 0
4 years ago
I don't know what the answer is because my calculator won't calculate it out
nadezda [96]
I got 230230.

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4 years ago
If I Row my canoe at 5 mph and I travel upstream at 3 mph, how fast will I be traveling downstream if I am rowing at the same ra
Assoli18 [71]
Is the same as the one you just did.

keep in mind that, going against the current, the current's speed erodes speed from your regular speed, whilst if you're going with the current, the current's speed adds to it.

now, in this case, you row 5mph, going upstream you're only doing 3mph, whatever happened to the other 2mph?  well, the current speed eroded them, meaning the speed of the river is 2mph.

now, going downstream with the current, your regular speed is 5mph, and the current is 2mph, since the current adds to yours, then you're going 5 + 2, mph.
5 0
3 years ago
Q6. A triangle has base 9 cm and perpendicular height 5.6 cm. Work out
Leto [7]

Answer:

I got 25.6cm² but I could be wrong

4 0
3 years ago
The length of a rectangular garden is 8 feet longer than it’s width. The garden is surrounded by a sidewalk that is 4 feet wide
Westkost [7]
Answer:

The length = 20
The width = 12 

Explanation:

Let the Length of the garden be L and the Width W 
Therefore the area of the garden = L*W 
But we know that L = W + 8 
Therefore the area of the garden can be expressed as W*(W + 8) 
When the brackets are expanded this equals W^2 + 8W

The area of the recctangle which includes the path and garden will have a length of L + 8 (ie the length of the garden + 4 feet at the top and 4 feet at the bottom) 
The width will be W + 8 (width of garden + 4 feet at the left and 4 feet at the right) 
Therefore the area will be (W + 8)*(L +8) 
Once again we know that L = W + 8 
Therefore the area of the path/garden = (W +8)(W +8 +8) 
=(W +8)(W +16) 
=W^2 +24W + 128 

We know that the path alone has an area of 320 square feet. Therefore if we subtract the area of the garden (W^2 + 8W) from the area of the path/garden the area left is the area of the path only 

Therefore W^2 + 24W + 128 - (W^2 + 8W) = 320 
W^2 + 24W + 128 - W^2 - 8W = 320 
Simplify 
16W + 128 = 320 
Subtract 128 from both sides of the equation 
16W = 192 
divide both sides of the equation by 16 
W = 12 
As L = W + 8 
L = 12 + 8 = 20 
7 0
3 years ago
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