The given complex ion is as follow,
[Ru (CN) (CO)₄]⁻
Where;
[ ] = Coordination Sphere
Ru = Central Metal Atom = <span>Ruthenium
CN = Cyanide Ligand
CO = Carbonyl Ligand
The charge on Ru is calculated as follow,
Ru + (CN) + (CO)</span>₄ = -1
Where;
-1 = overall charge on sphere
0 = Charge on neutral CO
-1 = Charge on CN
So, Putting values,
Ru + (-1) + (0)₄ = -1
Ru - 1 + 0 = -1
Ru - 1 = -1
Ru = -1 + 1
Ru = 0
Result:
<span>Oxidation state of the metal species in each complex [Ru(CN)(CO)</span>₄]⁻ is zero.
When
Nucleophile (Alkoxide) reacts with Alkyl Halide (
Substrate), Ether (
product) is formed with the elimination of
Leaving group (Iodide in this case).
This is
SN² a nucleophilic substitution reaction which takes place in primary alkyl halides. Reaction is given as,
Air has mass and density, and. cold air is denser than warm air.
The same amount of water as oil air