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2 years ago

How many molecules are there in 45 moles of diphosphorus trioxide?

Chemistry

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

$2.71(10^{25})$ molecules

Explanation:

Remember 1 mol is equal to Avogadro's number

$45 mol (\frac{6.02(10^{23}) molecules}{1 mol})$

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1/2 * m * v ^ 2 = mgh

viktelen [127]

C. the square root of 2gh

Explanation:

The square root of 2gh is equivalent to Torricelli's law in the equation.

given expression:

$\frac{1}{2}$ m v² = mgh

to find v, we make it the subject of the expression:

*multiply both sides of the equation by 2:

2 x( $\frac{1}{2}$ m v² )= 2 (mgh)

mv² = 2mgh

*cancel the mass, m appearing on both sides:

v² = 2gh

* find the square root of both side

v = √2gh

Learn more:

Expression brainly.com/question/11207748

#learnwithBrainly

4 0

2 years ago

These four ELEMENTS were found in early earth and they make up all living things.

VladimirAG [237]

Answer: True

Air is a mixture of many things; it's not just Oxygen, but Hydrogen, Carbon, and Nitrogen as well are made up of air. Fun fact: Nitrogen is actually more abundant in air

6 0

3 years ago

Read 2 more answers

Calculate the molar mass of cacl2

kirza4 [7]

Answer:

$\boxed {\boxed {\sf 110.98 \ g/mol}}$

Explanation:

The molar mass is the mass of a substance in grams per mole.

To find it, add the mass of each element in the compound. These masses can be found on the Periodic Table.

The compound given is:

$CaCl_2$

The compound has 1 Ca (calcium) and 2 Cl (chlorine).

Mass of Calcium

The molar mass of calcium is 40.08 g/mol
There is only one atom of Calcium in CaCl₂, so the number above is what we will use.

Mass of Chlorine

The molar mass of chlorine is 35.45 g/mol
There are two atoms of chlorine in CaCl₂, therefore we need to multiply the molar mass by 2.
35.45 * 2= 70.9 g/mol

Molar Mass of CaCl₂

Now, to find the molar mass, add the molar mass of 1 calcium and 2 chlorine.
40.08 g/mol + 70.9 g/mol =110.98 g/mol

The molar mass of CaCl₂ is <u>110.98 grams per mole. </u>

6 0

2 years ago

A student has two unopened 33 CL cans containing carbonated water. Can A has been stored in the garage 32 degrees and can B has

IgorC [24]

Answer:

A. Can A will make a louder and stronger fizz than can B.

Explanation:

The solubility of a gas in a liquid decreases as the temperature increases, so the warmer can will have more undissolved carbon dioxide.

The warmer can will be under greater pressure, so it will make a louder and stronger fizz.

7 0

3 years ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Svet_ta [14]

Answer:

$V_1=23.3~mL$

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

$C_1*V_1=C_2*V_2$