Distance Between Two Ships Two ships leave the same port at noon. Ship A sails north at 18 mph, and ship B sails east at 17 mph.
How fast is the distance between them changing at 1 p.m.? (Round your answer to one decimal place.)
1 answer:
Answer:
24.8 mph
Step-by-step explanation:
as we know if one sailed north and another east, the angle with respect to the port will be 90 degrees
This means that the distance of each ship to the pier can be the legs of a rectangular triangle
The distance of a ship from the other would be represented by the hypotenuse
h: Hipotenuse
c1: leg 1
c2: leg 2
By Pythagoras we know that the hypotenuse is equal to
h = √(c1^2 + c^2)
if we replace with the values we have left
h = √(18^2 + 17^2)
h = √(324 + 289)
h = √613
h = 24.758
we round a decimal place
h = 24.8
You might be interested in
You need 250-116=$134. At $15 a day this is 134/15=8.93 days approx. After 9 days you will reach $251.
The answer is b with the angles
<span>x2</span>+<span>y2</span>+6x+10y+9=<span>0
that is ur answer :)</span>
Answer: the graph is shifted 6 units down
Step-by-step explanation:
Step-by-step explanation:
5th 55566 I have been trying for the best for