Answer:
f^-1(x) is 6x + 48
f(x) = 1/6x - 8
To find f^-1(x) equate f(x) to y
That's
f(x) = y
y = 1/6x - 8
Next interchange the terms
We have
x = 1/6y - 8
Make y the subject
Multiply through by 6
We have
6x = y - 48
y = 6x + 48
Therefore f^-1(x) is 6x + 48
Hope this helps you
Kx^2-x-1=0
Kx^2-x=1
Kx^2=1+x
K=1+x/x^2
Answer:
Step-by-step explanation:
x₁ = 0 ; y₁=0 &
x₂ = 1 ; y₂=2
Slope =

Slope = 2