Answer:
4 − [(4b3 − 25b2 + 14b − 2) ÷ (4b − 1)] = - b² - 6b + 6
Step-by-step explanation:
The expression is given to be :
4 - [(4b³ - 25b² + 14b - 2) ÷ (4b - 1)]
To solve this expression, we follow the rule of BODMAS
According to this we will follow the order of operation that is first we will do the division.
⇒ (4b³ - 25b² + 14b - 2) ÷ (4b - 1)
By carrying the division using long division method,. We get,
So, (4b³ - 25b² + 14b - 2) ÷ (4b - 1) = b² - 6b + 2
Now, the expression reduces to : 4 - b² - 6b + 2
⇒ Expression becomes : - b² - 6b + 6
Hence, 4 − [(4b3 − 25b2 + 14b − 2) ÷ (4b − 1)] = - b² - 6b + 6
