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ivann1987 [24]
3 years ago
12

Find the area of the composite figure

Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0
Greetings and Happy Holidays!

Let Statements:

Let l represent the length of square
Let w represent the width of a square
Let b represent the base of a triangle
Let h represent the height of a triangle
Let r represent the radius of a semi-circle

Formula for the area of a square: A=lw

Input the values of the variables:
A=(18)(8)

<span>The Area of the Square is:
</span>\boxed {A=144}

Formula for the area of the Triangle(s): A=\frac{bh}{2}

Input the values of the variables:
A=2(\frac{(5)(8)}{2})

Solve using the order of operations.
A=2(\frac{40}{2})

A=2(20)

The Area of the Triangle is:
\boxed {A=40}

Formula for the area of a semi-circle: A=\frac{\pi r^{2}}{2}

Input
 the values of the variables:
A=\frac{\pi (9)^{2}}{2}

Solve using the order of operations.
A=\frac{(81)\pi}{2}

A=\frac{254.469}{2}

The Area of the Semi-Circle is:
\boxed {A=127.235}

Now, to find the total area of the composite shape, we must add up all the values:
A=A_{square}+A_{triangles}+A_{semi-circle}

Input the values of the variables:
A=(144)+(40)+(127.235)

Solve using the order of operations.
A=(184)+(127.235)

The Answer Is:
\boxed {A=311.235}

The total area of the composite shape is 311.235 ft²

I hope this helped!
-Benjamin

VMariaS [17]3 years ago
3 0
Area of the two triangles = 5*8 = 40 ft^2
Area of rectangle = 18*8 = 144 ft^2
Area of semicircle = 0.5*π*9^2 = 40.5π ft^2

Total area = 40 + 144 + 40.5π = 311 ft^2 (3 s.f.)
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Part b) The area of the two bases together is 2r^{2} \pi\ in^{2}

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