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2 years ago

Solve 2 1/4 - 1 2/5=?

Mathematics

1 answer:

leonid [27]2 years ago

3 0

Answer:

17/20

Step-by-step explanation:

2 1/4=9/4

1 2/5=7/5

--------------

9/4-7/5

45/20-28/20

17/20

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CD contains the points C at 4, D at 0, and E at 2.

horsena [70]

Answer:

the length of CD is 4

the length of DE is 2

the ratio of CD to DE is 2:1

Step-by-step explanation:

8 0

2 years ago

Hal earns n dollars per hour. Next month he

xenn [34]

Answer:

$Total = 1.02n$

Step-by-step explanation:

Given

$Earnings = n$

$Raise = 2\%$ --- <em>not 296</em>

$Total = n + 0.02n$

Required

Simplify the expression for total earning

The total amount is derived from:

$Total = Earnings + Raise * Earnings$

$Total = n + 2\% * n$

Express percentage as decimal

$Total = n + 0.02 * n$

Now, we can solve further:

$Total = n + 0.02n$

$Total = 1.02n$

<em>Hence, the simplified expression is 1.02n</em>

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2 years ago

Read 2 more answers

Help please I need the area of the whole shape

Zepler [3.9K]

I can tell u that the sides of the square is 48 because i just added 24 to 24. I feel like this is easy to answer but i’m not sure how to complete my answer... So sorryyyy

8 0

2 years ago

A= 1/2 h(a+b) solve for b

irakobra [83]

Answer and Step-by-step explanation:

Solve for b.

A = $(\frac{1}{2}) (h)(a+b)$

Divide by h and multiply by 2 from both sides.

$\frac{2A}{h} = a+ b$

Subtract a from both sides.

$(\frac{2A}{h} ) - a = b$

3 0

2 years ago

Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval [0,π].

Troyanec [42]

Answer:

Arc length $=\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

Arc length $=9.75053$

Step-by-step explanation:

The arc length of the curve is given by $\int_a^b \sqrt{1+[f'(x)]^2}\ dx$

Here, $f(x)=\int_0^{4.5x}sin(t) \ dt$ interval $[0, \pi]$

Now, $f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )$

$f'(x)=4.5sin(4.5x)$

Now, the arc length is $\int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx$

$\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

After solving, Arc length $=9.75053$

5 0

2 years ago