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velikii [3]
3 years ago
8

Which algebraic expression represents this phrase? the product of 86 and the depth of the river

Mathematics
2 answers:
Marizza181 [45]3 years ago
6 0
If "d" is used to represent the depth of the river, that product will be
  86d
Dmitriy789 [7]3 years ago
3 0

An algebraic expression is a mathematical phrase that contains numbers, variables (like x or y) and operators (like add,subtract,multiply, and divide).

We have to form the algebraic expression for the phrase

" The product of 86 and the depth of the river"

Let the depth of the river be 'd'

Therefore, the algebraic expression = Product of '86' and 'd'

= 86 \times d

= 86d.

Therefore, the algebraic expression for the given phrase is "86d".

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3 years ago
If Kevin wants a 90 average in math after 5 tests and his first 4 tests are 76, 92, 89 and 97 what does he need on the fifth tes
Keith_Richards [23]
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
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Now you need to solve for X, the unknown:
87
+
88
+
92
+
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4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
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3 years ago
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Can you please answer this question?
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300miles/20sec=?miles/1min
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