Answer:
Step-by-step explanation:
7). Since, ∠4 and ∠5 are the linear pair of angles,
m∠4 + m∠5 = 180° [Supplementary angles]
72° + m∠5 = 180°
m∠5 = 180° - 72°
m∠5 = 108°
8). Since, ∠6 and ∠7 are the vertically opposite angles,
Therefore, ∠6 ≅ ∠7
m∠6 = m∠7
3x + 94 = 9x - 38
9x - 3x = 94 + 38
6x = 132
x = 22
m∠6 = 3(22) + 94 = 160°
m∠7 = 9(22) - 38 = 160°
9). Since, ∠2 and ∠3 are the linear pair of angles, both the angles will be supplementary.
m∠2 + m∠3 = 180°
(13x + 54) + (2x + 36) = 180°
15x + 90 = 180°
15x = 90
x = 6
m∠2 = 13(6) + 54 = 132°
m∠3 = 2(6) + 36 = 48°
This is a polynomial of degree 4, because you have 4 roots real or imaginary:1st) x= 5 →(x-5)=0
2nd) x = - 3→(x+3) =0
3rd) x = -1+3i →(x+1-3i) = 0
and the 4th one that is not mentioned which is the conjugate of
-1+3i, that is -1-3i (in any polynomial if a root has the form of a+bi, there is always a conjugate root = a-bi)
4th) x= -1-3i→(x+1+3i) = 0
Hence the polynomial =(x-5)(x+3)((x+1-3i)(x+1+3i)
Solving the above will give you (unless I am mistaken, pls recalculate):
x⁴-9x²-50x-150<u />
<span>A = Area
L= Length = 15
W + widith = 10
A = 150
The pool area is
L = 10
w= 5
A= 50
So the area of the perimeter = 100 square meters</span>
Answer:
adding by 5
Step-by-step explanation:
,...............................
The answer is E because during 5:00-9:00 the temperature didn’t change
