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suter [353]
3 years ago
5

Subtract the second equation from the first 6x + 5y =16 - (6x + 2y=10)

Mathematics
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

3x = 6

Step-by-step explanation:

Combine:

6x + 5y =16

- (6x + 2y=10)

--------------------

     3y = 6, so that y = 2 (We weren't actually asked to find the solution.)

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Write the equation with both x= 8 and x= -8 as solution
nlexa [21]

Answer:

y = x^2 - 64

Step-by-step explanation:

Hello!

We can use the factored form of a Quadratic to find an equation with 8 and -8 as our solution.

<h3>Factored Form: y = a(x - h)(x - k)</h3>

The value in each parenthesis should be 0. So 8 and -8 can be flipped and used for h and k.

  • y = a(x - h)(x - k)
  • y = a(x - 8)(x+ 8)

This will give roots 8 and -8 for x.

  • y = 1(x - 8)(x + 8)\\
  • y = x^2 - 64

A possible equation is y = x^2 - 64.

5 0
2 years ago
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I need help with number 11 just the answers no need to show work!
evablogger [386]
I wish I could help but I can’t see the it
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3 years ago
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T
Ad libitum [116K]

Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180                      ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}

105^{\circ}+ m\angle B=180^{\circ}

Simplify:

m\angle B=75^{\circ}

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle  to the sines of its angles.

\frac{\sin A}{BC} = \frac{\sin C}{AB}

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}

then,

BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}

BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798 unit

Similarly for  AC:

\frac{\sin B}{AC} = \frac{\sin C}{AB}

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}

then,

AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}

AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283 unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

A = \frac{1}{2} \times AB \times AC \times \sin A

Substitute the values in above formula to get area;

A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}

A = 4 \times 10.9283 \times 0.86602540378

Simplify:

Area of triangle ABC = 37.856 (approx) square unit





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How to graph y&gt;1/3x+5
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