We get the gradient of the lines which is perpendicular to the given lines as 1/3, -8, 0 and -3/2.
We are given some equation of the lines and we need to find the gradient of the lines which are perpendicular to them.
For this, we will first find the slope of the lines and then reciprocal it and change their signs to obtain the gradient of the perpendicular lines.
a) y = -3 x + 11
Here we can see that the slope of the line is:
m = -3
So, the gradient of the perpendicular line will be:
m' = 1 / 3
b) - x / 4 + 2 y = 0
2 y = x / 4
y = x / 8
slope = m = 1 / 8
Gradient = m' = - 8
c) y = - 3
Slope = m = 0
Gradient = m' = 0
d) y = 2(x - 1) / 3
y = 2/3 x - 1/3
slope = m = 2/3
Gradient = m' = -3/2.
Therefore, we get the gradient of the lines which is perpendicular to the given lines as 1/3, -8, 0 and -3/2.
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Answer:
No
Step-by-step explanation:
For a relation to be a function, each value of x must map to exactly one unique value of y
Here x = 4 and x = 0 both map to y = 3
Thus the relation is not a function
21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000