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Nataly [62]
3 years ago
8

Euler's method:

Mathematics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

f(1) ≈ 2.7864

Step-by-step explanation:

You appear to want a couple of iterations of ...

... y[n+1] = y[n] +arcsin(x[n]·y[n]}·(x[n+1] -x[n])

... x[n+1] = x[n] +0.5

... x[0] = 0

... y[0] = 2

Filling in the values, we get

... y[1] = 2 + arcsin(0·2)·0.5 = 2

... y[2] = 2 + arcsin(0.5·2)·0.5 = 2 +(π/2)·0.5 ≈ 2.7864 . . . . corresponds to x=1

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KengaRu [80]
2 consecutive positive integers....x and x + 1
" the product " means multiply and " the sum " means add

x(x + 1) = x + (x + 1) + 1
x^2 + x = 2x + 2
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x^2 - x - 2 = 0
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x = -1......not this one because it is negative

x - 2 = 0
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3 years ago
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gtnhenbr [62]
<h2><u>solución</u></h2>

deja que los números sean x, and x + 2

sabemos que su suma es igual a 100, entonces

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y el segundo número es x + 2 = 49 + 2 = 51 (también es el mayor entre los dos números)

entonces suma de dígitos de mayor número = 5 + 1 = 6

Respuesta correcta de la pregunta anterior = 6

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