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dimulka [17.4K]
4 years ago
14

The random variable x is the number of vehicles that pass through an intersection in a 30-minute interval. It can be assumed tha

t the probability of an occurrence is the same in any two time intervals of an equal length. It is known that the mean number of occurrences in 30 minutes is 9. What is the expected value of the random variable x?
Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
8 0

Answer:

9 is the correct answer to the given question .

Step-by-step explanation:

AS mention  in the question the random variable x is the number of vehicles that passing through the intersection in the 30-minute .So we concluded that it is normal distribution because in the normal distribution the variable values are divided .

In the Normal distribution  

Mean \ number\ =\ Expected\  value\ \\Here Mean number\ =\ 9

Therefore the Expected value =9.

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Help plz and show work, please
Lena [83]

Answer:6.48

Step-by-step explanation:

1.60 times 4 jus to start it off it will be 6.40 plus the 1/2 pound it will be .80 plus 6.40 will be 7.20 and 10 percent off that is .72 the remainder will be 6.48

4 0
4 years ago
Read 2 more answers
Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
Mr. Smith goes to the concession stand and buys 2 soft pretzels and 1 cheeseburger for $8.25. Mr. Martin goes to the same conces
polet [3.4K]

Answer:

<em>$4.15</em>

Step-by-step explanation:

Let the cost of a cheeseburger be x

Let the cost of a soft pretzels be y

If Mr. Smith goes to the concession stand and buys 2 soft pretzels and 1 cheeseburger for $8.25, this is expressed as;

x + 2y = 8.25 .... 1

Also, if Mr. Martin goes to the same concession stand and buys 1 soft pretzel and 3 cheeseburgers for $13.50, this is expressed as;

3x + y = 13. 50..... 2

The required equations are:

x + 2y = 8.25

3x + y = 13. 50

Find x and y by solving simultaneously:

From 1: x + 2y = 8.25

x = 8.25 - 2y ..... 3

Substitute 3 into 2

3(8.25-2y)+y = 13.50

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24.75 - 5y = 13.50

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y = -10.25/-5

y = 2.05

Since x = 8.25 - 2y

x = 8.25 - 2(2.05)

x = 8.25 - 4.1

x = 4.15

<em>Hence the cost of a cheesburger is $4.15</em>

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3 years ago
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Just multiply 5:13 by any number
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4 years ago
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Evaluate the expression when y = 4. 5 + y + 8
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Answer: 17

Step-by-step explanation:

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3 years ago
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