Area of triangle = 1/2 x base x height
so old triangle we have 1/2 x b x h = 48
new triangle has base 3 times as long and height is half as long
so we would get:
1/2 x (3B) x (1/2H) = area
rewrite as 1/2 x 3/2 x b x H = area
divide by original are os 1/2 x b x h and you end up with 3/2
so new area = 3/2 x old area
new area = 3/2 * 48 = 72 square inches
First you plot in the y-intercept of the equation. To find the y-intercept, substitute 0 into x. -3m will cancel our giving you y=5. x=0, y=5, the first ordered pair is (0,5). Now after you plot in the y-intercept, use your slope, which is -3, to graph the points of the equation. Starting from (0,5), move down 3 spaces on the y-axis (because it’s -3) and you’ll end up at (0,2). Next move over 1 ( all slopes with just a whole number moves on the x-axis 1 since the whole number divided by 1 doesn’t change the slope number) to the right because it’s a negative linear equation so it’ll go downward. After moving right, you’ll get (1,2). Do a couple more points starting from (1,2) then the 3rd point ABD and so on to get 3 or more points to be able to draw a linear line.
Answer:
Step-by-step explanation:
First we multiply x through (y+1). This equals xy +x.
Second we take 3 through (y+1). This equals 3y+3.
Next we take xy + x through (x+2). This equals 2x squared, y + 2x squared.
Fourth we take 3y+3 through (x+2). This equals 6xy + 6x.
If the slope of AB = CD and BC = AD it's a parallelogram:
Slope of AB = 6+1 / -9+5 = -7/4
CD = -2-5 / 3+1 = -74
These are equal.
BC = 5-6 / -1 +9 = -1/8
AD = -2 +1 / 3+5 = -1/8
These are also equal so it is a parallelogram.
Now to find if the diagonals are perpendicular find the slope of the perpensicular points:
AC = 5 +1 / -1 +5 = 6/4 = 3/2
BD = 6+2 / -9 -3 = 8/-12 = -2/3
Because BD is the reciprocal of AC, this means they are perpendicular.
And because AB is not perpendicular to AD ( AB and AD are not reciprocals) it is a rhombus.
