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3 years ago

9

A certain model car has a keypad with 5 numbers on the door. To open the door, 5 numbers must be entered in the correct

1 answer:

MrRissso [65]3 years ago

8 0

Answer: A. $\dfrac{1}{120}$

Step-by-step explanation:

Total digits on keypad = 5

According to permutation,

If repetition of digits is not allowed then the number of 5-digits passwords can be formed = 5!

= 5 x 4 x 3 x 2 x 1 [n!=n x (n-1) x (n-2)x ... x 1]

=120

The probability that someone guesses the correct code = $\dfrac{\text{Number of correct codes}}{\text{Total possible codes}}$

$=\dfrac{1}{120}$

Hence, the correct option is A.

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Scott is playing a game in which he rolls a number cube with faces numbered 1through 6 and spins the spinner shown below one tim

defon

Solution:

The total number of possiblities rolling a number cube with faces numbered 1 to 6 is;

And the total number of possibilities spining the spinner is;

The number of possibility where outcome on the cube is greater than 2 is;

$4$

And the number on the spinner less than 9 is;

$2$

Hence, the unique combination is;

$4\times2=8$

CORRECT OPTION: A

7 0

1 year ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

3 years ago

Help me please 2(x-4) = 6x - 6

Dmitrij [34]

Answer:

-1/2

Step-by-step explanation:

2(x-4)=6x-6

2x-8=6x-6

2x-6x-8=-6

-4x-8=-6

-4x=-6+8

-4x=2

x=2/-4

simplify

x=-1/2

8 0

3 years ago

Read 2 more answers

Write An algebraic expression with the constant 7 and thee variable y

Snowcat [4.5K]

Y+7
Y is the variable and 7 is the constant.

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3 years ago

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The class decides to make chocolate chip cookies for Mr. Burn’s first day of school in September. Each student needs 3⁄4 of a st

VladimirAG [237]

Answer:

10 1/2 sticks, or 11 sticks with half a stick left over.

Step-by-step explanation:

If every student (and there are 14 students) needs 3/4 stick of butter, the equation is 3/4 x 14 = 10 1/2

3 0

3 years ago