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mel-nik [20]
4 years ago
13

An object slides down a very smooth ramp, with negligible friction. It slides with constant acceleration a under the action of t

wo forces: the supporting force n exerted by the ramp, and the force m g due to gravity exerted by the earth. What can you say about how the magnitude of n compares to the magnitude of m g?
1. n is less than m g.
2. Their magnitudes are equal, as is almost always true on the earth’s surface.
3. None of these
4. n is greater than m g.

Physics
1 answer:
sveta [45]4 years ago
3 0

Answer:

In statics condition and if is a body is over plane surface N = mg

In all cases which a body is on a ramp force N will be smaller than mg, and depending on the level of the ramp (bigger the ramp smaller force N)

Explanation:

See annex (Figure 1)

We can see with the help of force diagram the relation between  N force  and mg

Lets look first the body on the ramp assuming there is not movement

The  sum of forces alog y axis = 0

mg* cos∠ BAC = N (normal force)

So N is always a fuction of mg and of the cosine of the inclination angle, and the cosine of angle varies from value 1 when the angle is 0 (look the case where the block is on the surface without inclination N = mg ).

And as the inclination increase the value of cosine will become smaller and so will N force which is directly proportional of cosine of the inclination angle

Therefore we can say that force N is always minor than mg unless in extreme case where the block is over the surface in which case N takes its maximum value N = mg

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macmillan learning im Hamm at big bend Coty Conege A 1.30-m-long rope is stretched between two points with a tension that makes
san4es73 [151]

Answer:

0.87 m

70.6 Hz

Explanation:

L = length of the rope = 1.30 m

n = order of the harmonic = 3

\lambda = Wavelength

Wavelength is given as

\lambda = \frac{2L}{n}

\lambda = \frac{2(1.30)}{3}

\lambda = 0.87 m

v = Speed of transverse wave = 61.4 m/s

f = frequency of the third harmonic

frequency is given as

f = \frac{v}{\lambda }

f = \frac{61.4}{0.87}

f = 70.6 Hz

5 0
3 years ago
Two resistors connected in series have an equivalent resistance of 724.5 Ω, when they are connected in parallel, their equivalen
dybincka [34]

Answer:

544.65 ohm and 179.84 ohm

Explanation:

Hello

Let

Resistor 1 (R1) and Resistor 2 (R2)

in series R_{eq} =R1+R2      

in parallel

\frac{1}{R_{eqp} } =\frac{1}{R1} +\frac{1}{R2}\\\\R1=R_{eqs} -R2\\\\R1 =724.5-R2 (equation 1)\\ R_{eqp}}=\frac{R1*R2}{R1+R2}\\\\\ 135.2 = \frac{R1*R2}{R1+R2}(equation 2)\\\\\\\\replacing 1 in \ 2\\\\probema data

135.2=\frac{(724.5-R2)(R2)}{724.5-R2+R2} }\\135.2=\frac{(-R_{2} ^{2}+724.5R2) }{724.5}\\ 135.2*724.5=-R_{2} ^{2}+724.5R_{2}\\\\R_{2} ^{2} -724.5R_{2}  +97952.4 =0\\R_{2} =\frac{724.5 \±\sqrt{(-724.5^{2})-4(1)(97952.4) } }{2(1)}\\R_{2} =\frac{724.5\±\sqrt{(133092.25) } }{2(1)}\\\\R_{2} =\frac{724.5+364.81810}{2} \\R_{2} =544.65 ohm\\\\R_{2} =\frac{724.5-364.81810}{2} =179.84 ohm\\\\

let R2=544.65 and replace in equation 1

R1=724.5-544.65

R1=179.85

so, the resistors are 544.65 ohm and 179.84 ohm

Have a  great day

     

7 0
4 years ago
Rosalinda’s take-home pay is 1700 a month she spends 11% of her take-home pay on her cable bill how much is Rosalinda’s monthly
Marizza181 [45]

Answer:

Explanation:

To solve this simply put 11% in its decimal form (0.11) and multiply it by her take-home pay and boom that's yer answer 187

6 0
3 years ago
In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5
kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, \lambda=600\ nm=6\times 10^{-7}\ m

Slits separation, d=2.2\times 10^{-5}\ m

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

d\ sin\theta=n\lambda, n = 1

\theta=sin^{-1}(\dfrac{\lambda}{d})

\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})

\theta=1.56^{\circ}

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, d\ sin\theta=(n+\dfrac{1}{2})\lambda

sin\theta=\dfrac{3\lambda}{2d}

\theta=sin^{-1}(\dfrac{3\lambda}{2d})

\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})

\theta=2.34^{\circ}

Hence, this is the required solution.

4 0
4 years ago
A toy spacecraft is launched directly upward. When the toy reaches its highest point, a spring is released and the toy splits in
Murljashka [212]

Answer:

A

Explanation:

Momentum conservation will cause 0.08kg to move to the west (opposite of 0.02 kg).

and because both are at the same height above the ground, they will take the same time to reach the ground.

The speed of 0.08kg will be less than 0.02 kg, let v be the speed of 0..02kg, then speed of 0.08kg V is

0.02v - (0.08)V = 0

V = 0.02 v/ 0.08 = v/4

The speed of 0.08 kg = v/4

The speed of 0.08 kg is less than 0.02kg.

So 0.02kg strikes the ground farther from the launch point than does the 0.08 kg

8 0
3 years ago
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