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Anvisha [2.4K]
3 years ago
11

A student is studying calcium, a highly reactive element that humans need for strong bones. Which characteristic of calcium is m

ost closely related to its chemical reactivity?
A The 20 protons in each atom of calcium B The density of calcium, which is 1.54 g/cm3
C The atomic mass of calcium, which is 40.078 amu D The 2 valence electrons in each atom of calcium
Physics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:d

Explanation:

I took the quiz and I got that question right :)

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Pure substances can be classified as elements or compounds.

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4 years ago
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Answer:

I assume they want answer A, but it's a silly question.

Explanation:

Well, if we assume that the girls are applying equal force, as they are the same size and strength (apparently also the same resolve etc.).

Equal force in opposite directions means the composite force is null. An object that no force is applied to continues moving in the same direction, so if the doll was moving somewhere, it would keep doing so, except all of this makes no sense the doll is not in gravityless vacuum what are we even talking about.

The answer A is the least ridiculous.

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C. a lack of accurate results


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6 0
3 years ago
A 30.0-g object connected to a spring with a force constant of 40.0 N/m oscillates with an amplitude of 6.00 cm on a frictionles
Naddika [18.5K]

Answer:

a) 72mJ

b) 0.33m/s

c) 54mJ

d) 18mJ

Explanation:

(a) The total energy of the system is given by:

E_T=\frac{1}{2}kA^2

where k is the force constant and A is the amplitude. By replacing we get:

E_T=\frac{1}{2}(40N/m)(0.06m)^2=0.072J = 72mJ

(b) we can get the speed by the conservation of energy (the kinetic energy and potential energy must equal the total energy in any place):

E_T=E_k+E_p\\\\\frac{1}{2}kA^2=\frac{1}{2}mv^2+\frac{1}{2}kx^2\\\\v=\sqrt{\frac{kA^2-kx^2}{m}}=\sqrt{\frac{(40N/m)((0.06m)^2-(0.0115m)^2)}{0.03kg}}=0.33m/s

where we have used that x=1.15cm=0.0115m; A=6.00cm=0.06m

(c) Again, by the conservation of energy:

E_k=\frac{1}{2}k(A^2-x^2)=\frac{1}{2}(40N/m)((0.06m)^2-(0.03m)^2)=0.054J=54mJ

(d) E_p=\frac{1}{2}kx^2=\frac{1}{2}(40.0N/m)(0.03m)^2=0.018J=18mJ

hope this helps!!

6 0
3 years ago
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