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Oduvanchick [21]
3 years ago
8

What is 16% of £50 I need to know

Mathematics
2 answers:
algol133 years ago
8 0

first of all you get rid of the % by dividing by a 100...

so 16%/100=0.16

now you just multiply the 0.16 by the price as follows:

0.16 × £50 = £8 <== (final answer)

TEA [102]3 years ago
4 0

Answer: 8 UK£

Step-by-step explanation:

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The answer and how to do it.
Kruka [31]

let x = orginal price of the shorts

$21 = x(100%-20%) * 1.05

$21 = x(80%) * 1.05

$21 = 0.8x * 1.05

Subtract 1.05 from both sides

$19.95 = 0.8x

Divide 0.8 from both sides

$24.9375 = x

So the orginal price of the shorts are about $24.94

4 0
3 years ago
HELLPPPP PLEASE ASAP WILL MARK BRAINLIEST!! PLEASW AND THANK YOUUU!!!
blagie [28]

1. It is the product of a square, meaning it can be simplified to (x+10)(x+10) or (x+10)^2

8 0
3 years ago
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−2 1/2 −5 3/4 The distance between the two numbers is
emmainna [20.7K]

the answer to this question is -7.25 or 7 1/4

5 0
3 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
An equation in the form ax2+bx+c=0 is solved by the quadratic formula. The solution to the equation is shown below.x=−7±√ "572"
7nadin3 [17]

Answer:

B: a = 1, b= 7, c = -2

Explanation:

\sf Quadratic \ Equation : \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a}

Knowing This:

<u>solve for b</u>

  • -b = -7
  • b = 7

<u>solve for a</u>:

  • 2a = 2
  • a = 1

<u>solve c</u>:

  • b² - 4ac = 57
  • 7² - 4(1)(c) = 57
  • -4c = 57 - 49
  • -4c = 8
  • c = 8/-4 = -2
4 0
2 years ago
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