Answer:
-2/3
Step-by-step explanation:
Log125(1/25)=x
Raise each side to the base of 125
125^Log125(1/25)=125^x
1/25 = 125^x
Rewrite 25 as a power of 5 and 125 as a power of 5
1 / 5^2 = 5^3^x
The if power is in the denominator, we can bring it to the numerator by making it negative
5^-2 = 5^3^x
We know that a^b^c = a^(b*c)
5^-2 = 5^(3*x)
Since the bases are the same, the exponents are the same
-2 = 3x
Divide by 3
-2/3 = 3x/3
-2/3 =x
X-5 is your answer. hope that helps
(1)
f(x) + g(x) = 3x + 2 + 2x + 5 = 5x + 7
f(x) - g(x) = 3x + 2 - 2x - 5 = x - 3
(2)
f(x) + g(x) = 4x - 1 + 3x - 4 = 7x - 5
f(x) - g(x) = 4x - 1 - 3x + 4 = x + 3
(3)
f(x) + g(x) = - 5x + 3 + 2x - 4 = - 3x - 1
f(x) - g(x) = - 5x + 3 - 2x + 4 = - 7x + 7
(4)
f(x) + g(x) = 3x - 4 - 2x + 3 = x - 1
f(x) - g(x) = 3x - 4 + 2x - 3 = 5x - 7
(5)
f(x) × g(x) = - 2(- x + 7 ) = 2x - 14
(6)
f(x) × g(x) = - 5(2x - 7) = - 10x + 35
