When rolling two number cubes, what is the probability of rolling a sum that is 6 or a sum that is odd?
1 answer:
Answer:
The Probability is found as:
A) P = 23/36
Step-by-step explanation:
When two dices are rolled, each dice has a total outcomes of 6. The total number of outcomes of both dices is:
Find the pair of values (x₁ , x₂) for which sum is 6 or odd number, where x₁ is the number on first dice and x₂ is the number on the second dice.
(1,2),(1,4),(1,5),(1,6),(2,1),(2,3),(2,4),(2,5),(3,2),(3,3),(3,4),(3,6),(4,1),(4,2),(4,3),(4,5),(5,1),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)
So Desired number outcomes = 23
So, Probability is given as:
P = Desired number outcomes / Total number of outcomes
P = 23/36
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Answer:
Step-by-step explanation:
Hello!
Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"
X~Bi (n;ρ)
ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95
n= 390
x= 303
sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78
Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.
You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:
^ρ±* √[(^ρ(1-^ρ))/n]
=
= 2.58
0.78±2.58* √[(0.78(1-0.78))/390]
0.0541
[0.726;0.834]
With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.
I hope it helps!