When rolling two number cubes, what is the probability of rolling a sum that is 6 or a sum that is odd?
1 answer:
Answer:
The Probability is found as:
A) P = 23/36
Step-by-step explanation:
When two dices are rolled, each dice has a total outcomes of 6. The total number of outcomes of both dices is:
Find the pair of values (x₁ , x₂) for which sum is 6 or odd number, where x₁ is the number on first dice and x₂ is the number on the second dice.
(1,2),(1,4),(1,5),(1,6),(2,1),(2,3),(2,4),(2,5),(3,2),(3,3),(3,4),(3,6),(4,1),(4,2),(4,3),(4,5),(5,1),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)
So Desired number outcomes = 23
So, Probability is given as:
P = Desired number outcomes / Total number of outcomes
P = 23/36
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Answer:
The required point is, (7, -2)
Step-by-step explanation:
The straight line passing through (0,0) and (2,7) is,
y =
⇒ y = 3.5x --------------(1)
Now, the straight line perpendicular to this line and passing through (0, 0) is
y =
⇒ 7y + 2x = 0 -------------(2)
Let, (h,k) be the required point.
then, it is on the line 7y + 2x = 0
⇒7k + 2h = 0
⇒k = ------------(3)
Again, distance from (0,0) of (h, k) is same as that of (2,7)
⇒
⇒ = 53 [putting the value of k from (3)]
⇒ = 49
⇒h = 7 [since, (h,k) is in 4th quadrant, so,h >0]
So, k = -2 [putting the value of h in (3)]
So, the required point is, (7, -2)