When rolling two number cubes, what is the probability of rolling a sum that is 6 or a sum that is odd?
1 answer:
Answer:
The Probability is found as:
A) P = 23/36
Step-by-step explanation:
When two dices are rolled, each dice has a total outcomes of 6. The total number of outcomes of both dices is:
Find the pair of values (x₁ , x₂) for which sum is 6 or odd number, where x₁ is the number on first dice and x₂ is the number on the second dice.
(1,2),(1,4),(1,5),(1,6),(2,1),(2,3),(2,4),(2,5),(3,2),(3,3),(3,4),(3,6),(4,1),(4,2),(4,3),(4,5),(5,1),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)
So Desired number outcomes = 23
So, Probability is given as:
P = Desired number outcomes / Total number of outcomes
P = 23/36
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Answer:
m<E =
Step-by-step explanation:
From the diagram, ΔACE and ΔBDE are similar. So that comparing its angles, we have;
(8x + 4) = (9x - 5)
8x + 4 = 9x - 5
5 + 4 = 9x - 8x
x = 9
Thus,
(8x + 4) = 8(9) + 4 = 76
(9x - 5) = 9(9) - 5 = 76
3x = 3(9) = 27
From ΔACE,
3x + (8x + 4) + m<E = 180 (sum of angles in a triangle)
27 + 76 + m<E = 180
m<E = 180 - 103
m<E =