When rolling two number cubes, what is the probability of rolling a sum that is 6 or a sum that is odd?
1 answer:
Answer:
The Probability is found as:
A) P = 23/36
Step-by-step explanation:
When two dices are rolled, each dice has a total outcomes of 6. The total number of outcomes of both dices is:
Find the pair of values (x₁ , x₂) for which sum is 6 or odd number, where x₁ is the number on first dice and x₂ is the number on the second dice.
(1,2),(1,4),(1,5),(1,6),(2,1),(2,3),(2,4),(2,5),(3,2),(3,3),(3,4),(3,6),(4,1),(4,2),(4,3),(4,5),(5,1),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)
So Desired number outcomes = 23
So, Probability is given as:
P = Desired number outcomes / Total number of outcomes
P = 23/36
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Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²= [∑X₁² - (( ∑X₁)²/n₁)]=
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!