All categories

2 years ago

How do you find the area of this triangle?

Mathematics

1 answer:

lara [203]2 years ago

5 0

To find the area of the triangle, use the area of a triangle formula: Area= 1/2(base)(height). In this image, the base of the triangle is 5.9. The height is 6.8. To find this, you multiply 1/2*6.8*5.9 which will give you answer: 20.06

You might be interested in

7/2 inches by 3/2 inches?

miskamm [114]

Answer:

5.25 inches or $5 \frac{1}{4}$ inches

Step-by-step explanation:

I believe that the question is what do they multiply to..? If so, we start by making them both in decimal form:

7 / 2 = 3.5

3 / 2 = 1.5

Now, we multiply:

3.5 * 1.5 = 5.25

If you want fraction form, we can turn .25 to 1/4.

Fraction form: $5 \frac{1}{4}$

6 0

2 years ago

Find the length of the side labeled (45)

Karolina [17]

Answer:

Step-by-step explanation:

x = 6

8 0

2 years ago

Read 2 more answers

Robert owns two dogs. Each day, one dog eats

notsponge [240]

Answer:

1/3

Step-by-step explanation:

1) 1/6+1/6= 2/6

2) 2 and 6 can both be divide be 2.

2/2=1 and 6/2=3

6 0

2 years ago

Find P 20 of the following arithmetic sequence: 206, 212, 218, 224....

Yanka [14]

Answer:

$p_{20} = 1.25528$

P₀ = 206 and difference d = 6

Step-by-step explanation:

Step(i):-

Given that the arithmetic sequence

206,212,218,224,.....

P₀ = 206 and difference d = 212-206 = 6

The $n^{th}$ term of the sequence

$t_{n} = ar^{n-1}$

Step(ii):-

The $n^{th}$ term of the sequence

$P_{n} = ar^{n-1}$

Put n=20

$P_{20} = 206 ( 6) ^{20-1}$

$p_{20} = 1.25528$

7 0

2 years ago

Can someone help me with these? I need some help.

nata0808 [166]

Answer:

1) $\sqrt{569}$ 2) 8 3) 0.8 4) $\sqrt[10]{61}$

Step-by-step explanation:

The equation for pythagoream theorem is

a^2 + b^2 = c^2 (the caret "^" represents exponents)

A = a side length

B = another side length

C = the hypotnuse which is the slanted side of the right triangle.

To solve these problems plug in the known values into the equation then solve.

6 0

2 years ago