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3 years ago

How do you find the area of this triangle?

Mathematics

1 answer:

lara [203]3 years ago

5 0

To find the area of the triangle, use the area of a triangle formula: Area= 1/2(base)(height). In this image, the base of the triangle is 5.9. The height is 6.8. To find this, you multiply 1/2*6.8*5.9 which will give you answer: 20.06

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the healer gave Harold a deferred payment plan. The expression for the amount of Harold’s last payment is x - 100y

Step-by-step explanation:

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3 years ago

20 pounds of $4 written as a unit rate

borishaifa [10]

Answer:

20 pounds divided by $4= 5

Step-by-step explanation:

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3 years ago

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3 years ago

PLEASE HELP!!!<br> Solve for x: 3 over quantity x minus 4 equals 7 over x

uranmaximum [27]

Answer:

Solve for x

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Step-by-step explanation:

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2 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

3 years ago