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3 years ago

Four more than twice a number is -10.

Mathematics

2 answers:

Vadim26 [7]3 years ago

5 0

Answer:

4 + ( -7 X 2 ) = -10

Step-by-step explanation:

Check work:

-7 times 2 is -14.

4 + -14 = -10

amid [387]3 years ago

5 0

It is -10 hope it’s right

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I need help with this

Doss [256]

$\text{Apply Pythagorean theorem,}\\\\~~~~x^2 = 6^2 +8^2\\\\\implies x = \sqrt{6^2 +8^2}\\\\\implies x = \sqrt{36 +64}\\\\\implies x =\sqrt{100}\\\\\implies x = 10~~ \text{units.}$

3 0

1 year ago

Solve for the indicated variable 3x - y = 10; y

VashaNatasha [74]

Answer:

y = 3x - 10

Step-by-step explanation:

Starting with 3x - y = 10, add y to both sides:

3x = 10 + y

Then subtract 10 from both sides:

3x - 10 = y

If you switch the sides of the equation, it can also be written as:

y = 3x - 10

7 0

3 years ago

How do I solve this?

Delvig [45]

Answer:

10a + 2b

Step-by-step explanation:

Add the lengths of all sides:

3a + b + b + 2a - b + 3a + b + b + 2a - b

Now combine like terms:

10a + 2b

4 0

2 years ago

Identify the solution set of 3 In 4 = 2 In x. -{6} -{-8,8} -(8)

o-na [289]

Option C: The solution set is $\{8\}$

Explanation:

The expression is $3 \ln 4=2 \ln x$

Now, let us find the solution set.

Switch sides, we get,

$2 \ln x=3 \ln 4$

Dividing by 2 on both sides, we have,

$\ln x=\frac{3 \ln 4}{2}$

Thus, $\ln 4=\ln 2^2=2\ln 2$

Hence, the above expression becomes,

$\ln x=\frac{3 \cdot 2 \ln (2)}{2}$

Simplifying, we get,

$\ln x=3 \ln 2$

Applying the log rule, we get,

$$\ln x$=\ln \left(2^{3}\right)$

Simplifying, we have,

$$\ln x$=\ln \left8\right$

Applying the log rule, we have,

$x=8$

Thus, the solution set is $\{8\}$

Hence, Option C is the correct answer.

5 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago