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gtnhenbr [62]
3 years ago
6

Find the y-coordinate of the y-intercept of the polynomial function defined below. f(x)=2(3x+4)(x^2+2)

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
3 0

Answer:

Step-by-step explanation:

The best way to find out the answer to your question is to graph the cubic. As you can see, the y intercept is (0,16).

How was this obtained. notice that if x = 0 then

f(0) = 2(3*0+4)(0^2 + 2)

f(0) = 2(4)(2)

f(0) = 16 just as the graph tells us.

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A bus driver drives 547.25 miles on day one, on day 2 he drives 327.875. How many more miles did he drive on the first day then
Alika [10]

ANSWER: 219.375

subtract the second day from the first day.

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You took any loan of $9,015.20 to buy a car. The loan is to be paid back in 48 equal monthly payments how much is each payment r
stepan [7]

Answer:

<u>The equal monthly payment during 48 hours for buying a car is US$ 187.82</u>

Step-by-step explanation:

Loan from the bank to buy a car = US$ 9.015.20

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6 0
3 years ago
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

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b. between .025 and .05

6 0
3 years ago
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IRINA_888 [86]

Answer:

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8 0
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