Balanced chemical equation: C(s) + O₂(g) → CO₂(g).
Oxidation half reaction: C⁰ → C⁺⁴ + 4e⁻.
Reduction half reaction: O₂⁰ + 4e⁻ → 2O⁻².
Carbon is oxidized, it changes oxidation number from zero (in carbon element) to oxidation number +4 (in carbon dioxide).
Oxygen is reduced, it changes oxidation number from zero (in molecule of oxygen) to oxidation number -2 (in carbon dioxide).
Answer:
The formula weight of the compound is
46.069 g/mol.
Explanation:
Determine the molar mass from the empirical formula (C2H6O) by multiplying the molar mass of each element in the compound by the number of atoms of it and adding the resulting masses of the elements:
molar mass of C2H6O = (2 × 12.011 g/mol) + (6 × 1.008 g/mol) + (1 × 15.999 g/mol) = 46.069 g/mol.
Chemical properties can only be tested if you change the substance
Answer:
The answer to the question is 275 years
Explanation:
Here we have
The decay rate is given by
dN/dt = -λN
or dN/N = -λdt
Integrating the above equation with limits N and N₀ we have
㏑(N/N₀) = -λt
Note that the half life = (㏑ 2)/λ
From where λ = 0.693/5730 = 1.21 × 10⁻⁴
∴ ㏑(14.8/15/3) = -1.21 × 10⁻⁴ × t
or t = 275 years