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GenaCL600 [577]
3 years ago
5

When a substance is heated, what causes its properties to change?

Chemistry
2 answers:
hoa [83]3 years ago
8 0

The molecules vibrate when the substance is heated, and the shape of the substance begins to form a different shape. For example: when you hear up metal it will melt becuase its molecules are changing and moving.

sergey [27]3 years ago
6 0
Molecule movement. Ice is so hard because molecules are not moving, and the space between them are small. Hot water has bigger space between molecules that are always in motion.
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Which of the following statements is true? A. The process of meiosis forms daughter cells which are genetically identical to the
Marat540 [252]

Answer:

Mitosis results in the formation of two haploid gametes which can then combine to form a diploid daughter cell

Explanation:

Meiosis creates different cells

7 0
3 years ago
2) Is an atom with 26 protons and 30 neutrons an element or an isotope?*<br> Element<br> O Isotope
NikAS [45]
Does the element have a different amount of electrons than protons?
8 0
3 years ago
You have 1 mole of a gas at STP. If you apply the ideal gas law what is the approximate volume of the gas?
goldfiish [28.3K]

Answer:

A) 22.4L

Explanation:

we know, ideal gas law states

PV=nRT

V=nRT/P

At STP,

T= 273.15K     P=1atm         R=0.082L.atm/mol/K          n=1 mole

V=(1*0.082*273.15)/ 1

V=22.4L

7 0
3 years ago
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25 °C) form ideal solutions in all proportions. Let x1
jekas [21]

Answer:

y1 = 0.3162

y2 = 0.6838

Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

2-propanol P2° = 45.2 Torr

From Raoults law:

P(1-propanol) = P⁰ × X(1-propanol)

P(1-propanol) = 20.9 torr × 0.45 = 9.405

P(1-propanol) = 9.405 torr

Also P(2-propanol) = P⁰ × X(2-propanol)

P(2-propanol) = 45.2 torr × 0.45

P(2-propanol) = 20.34 torr

but the total pressure = sum of individual pressures

total pressure = 9.405 + 20.34

total pressure = 29.745 torr

given that y1 and y2 represent the mole fraction of each in the vapor phase

y1 = P1 / total pressure

y1 = 9.405/29.745

y1 = 0.3162

Since y1 + y2 = 1

y2 = 1 - y1

∴ y2 = 1 -  0.3162

y2 = 0.6838

cheers, i hope this helps.

7 0
3 years ago
Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur
Alenkinab [10]

Answer:

\large \boxed{\text{-10.0 kJ}}

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}

The negative sign indicates that the work was done against the surroundings.

4 0
3 years ago
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