Answer: 310K
Explanation:
Given that:
Volume of Chlorine gas V = 10.2L
Temperature T = ?
Pressure P = 1.83 atm
Number of moles of chlorine gas N = 0.734 moles
Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.83atm x 10.2L= 0.734 moles x 0.0821 atm L K-1 mol-1 x T
18.67atm L = 0.0603 atm L K-1 x T
T = (18.67atm L / 0.0603 atm L K-1)
T = 309.8K (Round up to 310K)
Thus, the temperature of the chlorine gas is 310 kelvin
Answer:
<h2><em><u>B.) lone pairs of electrons</u></em></h2>
Explanation:
The table below indicates the “Molecular Geometry” of the central atom depending on whether the groups of electrons around it are covalent bonds to other atoms or simply lone pairs of electrons.
Answer:
The answer to your question is 900 g of water vapor
Explanation:
Data
mass of H₂O = ?
mass of butane = 580 g
Balanced chemical reaction
2C₄H₁₀ + 13O₂ ⇒ 8CO₂ + 10H₂O
Process
1.- Calculate the molar weight of butane and water
Butane (C₄H₁₀) = 2[(12 x 4) + (1 x 10)]
= 2[48 + 10]
= 2[58]
= 116 g
Water (H₂O) = 10[(1 x 2) + (1 x 16)]
= 10[2 + 16]
= 10[18]
= 180 g
2.- Use proportions and cross multiplication to find the mass of water vapor
116 g of butane ------------- 180 g of water
580 g of butane ---------- x
x = (580 x 180) / 116
x = 900 g of water vapor
Answer:
A. Element
B. Compound
C. Compound
D. Element
E. Compound
F. Compound
Explanation:
Elements are what is already on the periodic table and compounds are the substances created when they are combined.
