When adding/subtracting variables you can only add/subtract those variable that are of the same power....
3x^3-2x+8+2x^2+5x+x^3+2x^2-3x-3
(3x^3+x^3)+(2x^2+2x^2)+(-2x+5x-3x)+(8-3)
4x^3+4x^2+5
There’s a Pythagorean triple and then draw it out the sides and then figure out the angles from the sides simple because of a direct relationship with quantity. And then the smallest angle is the one across from 3 so you start with three and then the hypotenuse is 5 so it’s 3/5 because sine=opposite/hypotenuse.
Looking at this, the unit of 1 length is equal to 2.5 units of width. To find 6 units of length, you just multiply 6 by 2.5. Getting this gives us 15. So your answer is C.
Answer:
14
Step-by-step explanation:
The law of cosines is a² = b²+c²-2bc(cos A).
We will use s in place of a, since it is the unknown side. This makes b and c 8 and 9.
Angle A will be the angle opposite side a, or in this case side s. This makes it 111.
This gives us
s² = 8²+9²-2(8)(9)(cos 111)
s² = 64+81-2(8)(9)(cos 111)
s² = 145-144(cos 111)
s² = 196.605
Take the square root of each side:
√(s²) = √(196.605)
s = 14.02 ≈ 14
