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liubo4ka [24]
3 years ago
9

Law of cosines: a2 = b2 + c2 -2bccos(A) What is the value of s to the nearest whole number?

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
8 0

Answer:

14

Step-by-step explanation:

The law of cosines is a² = b²+c²-2bc(cos A).

We will use s in place of a, since it is the unknown side.  This makes b and c 8 and 9.

Angle A will be the angle opposite side a, or in this case side s.  This makes it 111.

This gives us

s² = 8²+9²-2(8)(9)(cos 111)

s² = 64+81-2(8)(9)(cos 111)

s² = 145-144(cos 111)

s² = 196.605

Take the square root of each side:

√(s²) = √(196.605)

s = 14.02 ≈ 14

tatiyna3 years ago
6 0

Answer:

14

Step-by-step explanation:

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A charter fishing company buys a new boat for $224,000 and assumes that it will have a trade-in value of $115,200 after 16 years
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First, according to the information, we build a linear model, and then, the model is used to find the information asked.

a) The linear model is:

V(t) = 224000 - 6800t

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c) The depreciated value falls below $100,000 after 18.24 years.

d) The sketch is given at the end of the answer.

Item a:

  • The initial value is of $224,000, thus, the y-intercept of the linear function is of b = 224000.
  • The value decayed to $115,200 in 16 years, thus, the slope of the linear function is:

m = \frac{115200 - 224000}{16} = -6800

Then, the linear model is:

V(t) = 224000 - 6800t

Item b:

The value after 10 years is V(10), so:

V(10) = 224000 - 6800(10) = 156000

Then, the depreciated value of the boat after 10 years is of $156,000.

Item c:

This is t for which: V(t) = 100000. So

V(t) = 224000 - 6800t

100000 = 224000 - 6800t

6800t = 224000 - 100000

6800t = 124000

t = \frac{124000}{6800}

t = 18.24

The depreciated value falls below $100,000 after 18.24 years.

Item d:

The sketch is appended at the end of this answer.

A similar problem is given at brainly.com/question/24978772

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