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4 years ago

What is the sum of 3x^3-2x+8, 2x^2+5x and x^3+2x^2-3x-3 PLEASE HELP

Mathematics

2 answers:

sdas [7]4 years ago

8 0

Answer:

The sum of given expressions is $4x^3+4x^2+5$ .

Step-by-step explanation:

The given expressions are

$3x^3-2x+8,2x^2+5x,x^3+2x^2-3x-3$

We have find the sum of all these expressions.

$3x^3-2x+8+2x^2+5x+x^3+2x^2-3x-3$

Combine like terms.

$(3x^3+x^3)+(2x^2+2x^2)+(-2x+5x-3x)+(8-3)$

$4x^3+4x^2+(0)+(5)$

$4x^3+4x^2+5$

Therefore the sum of given expressions is $4x^3+4x^2+5$ .

ss7ja [257]4 years ago

4 0

When adding/subtracting variables you can only add/subtract those variable that are of the same power....

3x^3-2x+8+2x^2+5x+x^3+2x^2-3x-3

(3x^3+x^3)+(2x^2+2x^2)+(-2x+5x-3x)+(8-3)

4x^3+4x^2+5

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A) .9423

Step-by-step explanation:

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2 years ago

If n is an even integer between 1 and 1989, what is the probability that n^2 is divisible by 8

pantera1 [17]

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0.249874

Step-by-step explanation:

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3 years ago

What is equivalent to 4:3

kap26 [50]

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the answer is 6:8 or 9:12

Step-by-step explanation:

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3 years ago

Items are inspected for flaws by two quality inspectors. Both inspectors inspect every item and the probability that an item has

Genrish500 [490]

Answer:

a)0.976

b)0.00926

c)0.2402

d)0.35

Step-by-step explanation:

Let $X_i$ be an item passed by inspector i

Let Y be the event that there is a fault in an item

The probability that an item has a flaw is 0.1 i.e. P(Y)=0.1

If a flaw is present ,it will be detected by the first inspector with probability 0.92 i.e. $P(\bar{X_1}|Y)=0.92$

So, $P(X_1|Y)=1-0.92=0.08$

If a flaw is present ,it will be detected by the second inspector with probability 0.7 i.e. $P(\bar{X_2}|Y)=0.7$

So, $P(X_2|Y)=1-0.7=0.3$

If an item does not have a flaw, it will be passed by the first inspector with probability 0.95 i.e. $P(X_1|\bar{Y}) = 0.95$

So, $P(\bar{X_1}|\bar{Y}) = 1-0.95=0.05$

If an item does not have a flaw, it will be passed by the second inspector with probability 0.8 i.e. $P(X_2|\bar{Y}) = 0.8$

So, $P(\bar{X_2}|\bar{Y}) = 1-0.8=0.2$

a)P(found by atleast one inspector | It has flaw )=1-P(found by none inspector | It has flow )

P(found by atleast one inspector | It has flaw )= $1-P(X_1|Y) P(X_2|Y)$

P(found by atleast one inspector | It has flaw )= $1-0.08 \times 0.3$

P(found by atleast one inspector | It has flaw )=0.976

Hence the probability that it will be found by at least one of the two inspectors if it has flaw is 0.976

b) $P(Y|X_1)=\frac{P(X_1|Y) P(Y)}{P(X_1|Y) P(Y)+P(X_1|\bar{Y}) P(\bar{Y})}$

$P(Y|X_1)=\frac{0.08 \times 0.1}{0.08 \times 0.1+0.95 \times 0.9}=0.00926$

C)P( two inspectors draw different conclusions on the same item)= $P(X_1 \cap \bar{X_2} \cap Y)+P(\bar{X_1} \cap X_2 \cap Y)+P(X_1 \cap \bar{X_2} \cap \bar{Y})+P(\bar{X_1} \cap X_2 \cap \bar{Y})$

P( two inspectors draw different conclusions on the same item)=0.2402

$P(Y|(X_1 \cap X_2))=\frac{P(Y \cap X_1 \cap X_2)}{P(X_1 \cap X_2)}\\P(Y|(X_1 \cap X_2))=\frac{P(Y \cap X_1 \cap X_2)}{P(X_1 \cap X_2 \cap Y)+P(X_1 \cap X_2 \cap \bar{Y})}\\P(Y|(X_1 \cap X_2))=0.35$

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3 years ago

(6 x10^2) divided by (3 x 10^-5)<br> Give your answer in standard form.

alukav5142 [94]

The ansser is 2x10^-3 sorry for the mistake i’m french

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3 years ago