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3 years ago

Find the area of an equilateral triangle with side lengths of 12cm.

Mathematics

1 answer:

crimeas [40]3 years ago

5 0

Answer:

Step-by-step explanation:

To find the area of a equilateral triangle you must multiply the side length's of the triangle and then divide it by 2 because when you multiply the side length's it is giving you the area of a square which is 2x the triangle. That is why you divide.

Answer:72

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At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st

EastWind [94]

Answer:

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

Step-by-step explanation:

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = $\frac{609}{58} = 10.5$

Checking for ratios of the given options:

A. $\frac{483}{42} =11.5$

B. $\frac{378}{28} =13.5$

C. $\frac{504}{48} =10.5$

D. $\frac{560}{56} =10$

E. $\frac{315}{30} =10.5$

Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.

7 0

2 years ago

Read 2 more answers

In 1945, an organization asked 1467 randomly sampled American citizens, "Do you think we can develop a way to protect ourselve

patriot [66]

Yes.

1467-776=691

Which means 776 believed the country was protected and 691 believed the country wasn't.

7 0

2 years ago

Find the perimeter of the triangle shown

disa [49]

The Perimeter is 15 inches

6 0

2 years ago

Read 2 more answers

insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of

ss7ja [257]

Answer: $(13.22\%,\ 19.34\%)$

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : $\hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628$

$=16.28\%$

Significance level : $\alpha= 1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Confidence level for population proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)$

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= $(13.22\%,\ 19.34\%)$

7 0

3 years ago

Please help 25 points

Maksim231197 [3]

Answer:

5400

Step-by-step explanation:

look at the photo it shows the problems that

7 0

2 years ago