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2 years ago

12

Which of the following does NOT represent a straight line?

1 answer:

zhuklara [117]2 years ago

6 0

Y=x^2+7. That one is a quadratic function. It represents a parabola.

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Step-by-step explanation:

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2 years ago

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Explain how to plot the point (3, –7) on the coordinate plane.

Reil [10]

Coordinates are written in the form (x,y), x being a certain length along the horizontal x axis and y being a certain height along the vertical y axis. Positive y numbers are in the top half of the plane and negative y numbers are on the bottom. Positive x numbers are on the right side of the plane and negative x numbers are on the left. Therefore, (3,-7) would be 3 across to the right from the origin (where the x and y axes intersect) at (3,0) and 7 downwards from that point to (3,-7).

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2 years ago

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Write each of the following expressions without using absolute value: |z−6|−|z−5|, if z<5

abruzzese [7]

Answer:

The answer is <em>1</em>.

Step-by-step explanation:

Given the expression:

$|z-6|-|z-5|,\ if\ z$

To find:

The expression without absolute value.

Solution:

First of all, let us learn about the absolute value function:

$y = f(x) = |x| =\left \{ {{x\ if\ x>0} \atop {-x\ if\ x$

i.e. value is x if x is positive

value is -x if x is negative

Here the given expression contains two absolute value functions:

$|z-6|$ and $|z-5|$

Using the definition of absolute value function as per above definition.

$|z-5| =\left \{ {{(z-5)\ if\ z>5} \atop {-(z-5)\ if\ z$

$|z-6| =\left \{ {{(z-6)\ if\ z>6} \atop {-(z-6)\ if\ z$

Now, it is given that z < 5 that means z will also be lesser than 6 i.e. z < 6

So, given expression $|z-6|-|z-5|,\ if\ z$ will be equivalent to :

$-(z-6) - (-(z-5))\\\Rightarrow -z+6 +z-5 = \bold{1}$

So, the expression is equivalent to <em>1</em>.

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3 years ago

Please help<br><br> See the picture <br><br><br> Line A , B , C OR D ?<br><br> Help

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Answer:

It's the one on the bottom left

Step-by-step explanation:

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2 years ago