The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
2. 653.5 m^3
3. 706.9 m^3
4. 141.4 m^3
5. 2309.1 m^3
6. 402.1 m^3
7. 1900.1 m^3
8. 2001.2 m^3
9. 461.8 m^3
Answer with factoring: 2(3y+4)
Answer with simplifying: 6y+8
There no way that you can make this a mixed number unless you don't simplify all the way, which goes against the laws of math. I guess a fraction out of the answer would be 1189/1...