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tresset_1 [31]
2 years ago
5

A single ball is taken at random from an urn containing 10 balls numbered 1 through 10. what is the probability of obtaining a b

all whose number is less than 7?
Mathematics
1 answer:
kotykmax [81]2 years ago
7 0

To find probability you can use proportions

What i would do is 6/10 since it cant be 7 and then cross multiply it by 1/10.

This should get you 60%

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Find BC, please i need help!!
Trava [24]

İf you have anything that not Clear,respond me

5 0
3 years ago
find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2}
\\\\\\
d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2}
\\\\\\
d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-5&1&5
\end{array}
\\\\\\\
[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
Circumference and Area of a circle <br><br> #5 please
vlada-n [284]

Answer: the circumference is 25.13 and the area is 50.26 if rounding up then 50.27

Step-by-step explanation: to find circumference it is 2piR and to find the area it is piR^2

4 0
3 years ago
What is the answer and how do I solve it?
vichka [17]
The lengths of the rectangles are 7 and 12 respectively.  Form the ratio 7/12.  The widths of the rects. are x and 5 respectively.  Form the ratio x/5.  Now equate these two ratios:

7       x
--- = ---
12     5

Solve this for x.  One way to do this would be to cross-multiply, obtaining 12x = 35, and solving this result for x.  x will be a fraction.  Write the numerator and denominator in the boxes given.
4 0
2 years ago
I need help that is simple enough explnation
velikii [3]

Answer:

7 in both boxes

Step-by-step explanation:

In the picture, it shows

4 (x - 3) = 20

and then it shows

4 (x) - 4 (3) = 20

so practically you separate the x and 3 and put them in parentheses and then put a 4 next to both of them.

It should be the same as your question.

7 x (8 - 3)

and then separate 8 and 3 and put a 7 next to both of them.

( 7 x 8) - ( 7 x 3)

Hope it helps and have a great day! =D

~sunshine~

3 0
2 years ago
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