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arsen [322]
2 years ago
12

The distribution of income tax refunds follow an approximate normal distribution with a mean of $7010 and a standard deviation o

f $43. All of the income tax returns claiming the largest 0.15 % of refunds will be audited. Use the Empirical Rule to determine approximately above what dollar value must a refund be before it is audited.
Mathematics
1 answer:
Andrej [43]2 years ago
5 0

Answer:

A refund must be above $7,139 before it is audited.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 7010, standard deviation = 43.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

The empirical rule is symmetric, which means that the lowest (100-99.7)/2 = 0.15% is at least 3 standard deviations below the mean, and the upper 0.15% is at least 3 standard deviations above the mean.

Use the Empirical Rule to determine approximately above what dollar value must a refund be before it is audited.

3 standard deviations above the mean, so:

7010 + 3*43 = 7139.

A refund must be above $7,139 before it is audited.

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What are the domain and range of the function f(x) = 3x + 5
fredd [130]

Step-by-step explanation:

Here,let x = 1,2,3 and 4

Then,

Domain =(1,2,3,4)

Again,

f(1)= 3*1 + 5

=3 + 5

=8

f(2)=3*2 + 5

=6 + 5

=11

f(3)=3*3 + 5

=9 + 5

=14

f(4)=3*4 + 5

=12 + 5

=17

Therefore, Range=(8,11,14,17)

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Answer: 3

3x4 is 12

Hope this helps!
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If someone could please walk me through on how to answer this.
Elis [28]

To isolate c means to separate it completely on one side of the equals sign.


To isolate variables, you apply opposite operations.


In E = mc², m and c are being multiplied together. To separate them, you divide by the variable you want to get rid of. However, you must do this to both sides of the equation always. Whatever you do to one side of the equation you must do to the other side as well. This is so the equation remains true.


Since we want to isolate c, we'll start by dividing both sides by m.


E = mc²

E/m = mc²/m

E/m = c²  --  The m's cancel as 1


Now we have c squared. The opposite of squaring something is taking its square root. Take the square root of each side.


E/m = c²

√(E/m) = √(c²)

√(E/m) = c  --  Opposite operations cancel each other out


And you've isolated c!


Answer:

c = √(E/m)

3 0
3 years ago
Find the sum of the first 20 terms of an arithmetic sequence with an 18th term of 8.1 and a common difference of 0.25.
il63 [147K]

The sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5

Given,

18th term of an arithmetic sequence = 8.1

Common difference = d = 0.25.

<h3>What is an arithmetic sequence?</h3>

The sequence in which the difference between the consecutive term is constant.

The nth term is denoted by:

a_n = a + ( n - 1 ) d

The sum of an arithmetic sequence:

S_n = n/2 [ 2a + ( n - 1 ) d ]

Find the 18th term of the sequence.

18th term = 8.1

d = 0.25

8.1 = a + ( 18 - 1 ) 0.25

8.1 = a + 17 x 0.25

8.1 = a + 4.25

a = 8.1 - 4.25

a = 3.85

Find the sum of 20 terms.

S_20 = 20 / 2 [ 2 x 3.85 + ( 20 - 1 ) 0.25 ]

         = 10 [ 7.7 + 19 x 0.25 ]

         = 10 [ 7.7 + 4.75 ]

         = 10 x 12.45

         = 124.5

Thus the sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5

Learn more about arithmetic sequence here:

brainly.com/question/25749583

#SPJ1

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