![f(x)=2( \sqrt[3]{27})^{2x}](https://tex.z-dn.net/?f=f%28x%29%3D2%28%20%5Csqrt%5B3%5D%7B27%7D%29%5E%7B2x%7D%20)
Here 2 on left most side is the coefficient, 2x is the exponent and the of the function is cube root of 27.
So,
Thus, the simplified base for the function is 3. So correct answer is option B
Step-by-step explanation:
blue: 4x+2+7x+7+5x -4 = 16x +5
red: x+3+x+7+2x-5 = 4x -5
difference: 16x+5 - (4x -5) = 12x +10
Answer:
D
Step-by-step explanation:
To find a situation for 60−15x≥7, look for a story where 60 is a constant value that is decreasing by 15 for a number of times and where equal to or at least 7 is an option.
A. x would be weeks and it would decrease by 7x. This is not it.
B. 15 songs packages would have x be the number of packages not the price. This is not it.
C. This doesn't work either because if you want to owe them less than 7 it would have the sign < not >.
D. You have 60 to spend and you decrease it by $15 for each hat you buy till you save $7. This is it.
Answer:
58
Step-by-step explanation:
20-5= 15
15+43= 58
Answer:
so what is the question ??
Step-by-step explanation: