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krek1111 [17]
3 years ago
15

What the precents and decimals of these fraction 5/8. 66/200. 5 2/5. 2 7/16. has to be simplyed

Mathematics
1 answer:
Anit [1.1K]3 years ago
4 0
To find the percent, divide the top number by the bottom. ex:
1/2 equals 1 divided by 2.
when you put this in a calculator, it will say .5 , this means it is 50% ( you move the decimal over 2 to the right)
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You are about to take the road test for your​ driver's license. You hear that only 38​% of candidates pass the test the first​ t
OLga [1]

Answer:

Answers may vary but will most likely be close to 2.

Step-by-step explanation

  1.        Given:

                 first test:38%

                 second test:76%

    SIMULATION FIRST TEST

Randomly select a 2-digit number.

If the digit is between 00 and 35 then you passed the test,else you did not pass the test.

SIMULATION SECOND TEST

Randomly select a 2-digit number.

if the digit is between 00 and 75 then you passed the test,else you did not pass the test.

SIMULATION TRIAL

Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.

Record the number of trials needed to pass the first or second test.

Repeat 20 times and take the average of the 20 recorded number of trials

(what is the sum of recorded values divided by 20).

Note:you will most likely obtain a result of about two trials needed.

7 0
3 years ago
X + 3y = 45<br><br> What is the value of X what is the value of y
Sonja [21]
There are multiple different answers to this question. One of them could be x=0 and y=15. Another is x=12 and y=11. There's no exact correct number
3 0
4 years ago
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Solve showing all work and simplify completely: 9/18 + 1/3 =
Rina8888 [55]

9/18+1/3= 10/21

thats the answer

3 0
2 years ago
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Please help me answer this question
MAXImum [283]

Step-by-step explanation:

BC is the bisector of \angle ABQ

\therefore \angle ABC \cong \angle CBQ..(1)\\\angle CBQ \cong \angle CAB..(2) \\(\angle 's\: in \: alternate\: segments) \\

From equations (1) & (2)

\angle ABC \cong \angle CAB\\\therefore AC = BC

(Because sides opposite to equal angles are equal)

Hence Proved

7 0
3 years ago
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fredd [130]
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4 0
3 years ago
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