Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
An equilateral triangle has 3 congruent sides so the 2 expressions above are equal
3x - 9= 23 - 5x
And then you solve for x
-22=-2x
X=11
Answer:
1:0.33
Step-by-step explanation:
This is because one foot= .333 yards
I hope this is what you were asking! :)
See attachment file below.
Hope it helped!!
Answer:
the 2nd answer
Step-by-step explanation:
it makes sense
