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3 years ago

1/10 from fraction to deciamls

Mathematics

1 answer:

Crank3 years ago

8 0

0.1 hope this helps bb ♡

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n many population growth problems, there is an upper limit beyond which the population cannot grow. Many scientists agree that t

givi [52]

Answer:

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

Step-by-step explanation:

The logistic function of population growth, that is, the solution of the differential equation is as follows:

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

We use this equation to find the value of r.

In this problem, we have that:

$K = 16, P_{0} = 2, P(50) = 4$

So we find the value of r.

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

$4 = \frac{16*2e^{50r}}{16 + 2*(e^{50r} - 1)}$

$4 = \frac{32e^{50r}}{14 + 2e^{50r}}$

$56 + 8e^{50r} = 32e^{50r}}$

$24e^{50r} = 56$

$e^{50r} = 2.33$

Applying ln to both sides of the equality

$50r = 0.8459$

$r = 0.017$

The differential equation is

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

3 0

3 years ago

What is the equation of line b?

DerKrebs [107]

You are correct D is right

6 0

3 years ago

Hello can someone please do this for me. i literally need help so bad pls pls pls anything helps :(

iVinArrow [24]

The simplest form is 2 with working out shown on photo

6 0

3 years ago

A card is chosen at random from a deck of 52 cards. It is replaced, and a second card is chosen. What is the probability that bo

Citrus2011 [14]

Answer is C. 1/169
first we find how many cards are jacks in a deck: 4 out of 52 cards.
4/52 = 1/13 ( We have a 1 in 13 chance of drawing a jack)
(1/13)(1/13) = 1/169
( because the first card is replaced, we know that we don't have to change probabilities)(it will still be a 4/52 chance of drawing a jack)

4 0

3 years ago

Elevation is a measure of height in relation to sea level. The highest feature on Earth is Mount Everest with an elevation +29,0

Sphinxa [80]

Answer:

$Sea\ Level = 0\ ft$

The farthest point is the Challenger Deep

Step-by-step explanation:

Given

$Highest = +29029ft$

$Least = -35,797ft$

Solving (a): The sea level

Both elevations had signs in front of them.

The sea level is the point at the neutral level, neither positive nor negative.

Hence:

$Sea\ Level = 0\ ft$

Solving (b): Farthest Point.

The farthest point is the one with the highest magnitude.

Comparing

$Highest = +29029ft$ to $Least = -35,797ft$

-35,797 ft has the highest magnitude.

Hence:

<em>The farthest point is the Challenger Deep</em>

5 0

3 years ago

1/10 from fraction to deciamls​

1/10 from fraction to deciamls