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Mrac [35]
2 years ago
7

(-4x^5)^2(-2x^4)^5 Please help????!

Mathematics
1 answer:
ycow [4]2 years ago
8 0

Answer:

-512x^{30}

Step-by-step explanation:

(-4x^5)^2 = 16x^{10}\\(-2x^4)^5 = -32x^{20}\\16x^{10} * -32x^{20} = -512x^{30}

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The sum of c and 9 is equal to 16​
amid [387]

Answer:

c = 7

Step-by-step explanation:

The sum means to add c and 9, that is

c + 9 = 16 ( subtract 9 from both sides )

c = 16 - 9 = 7

5 0
3 years ago
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Find the value of c.....
Makovka662 [10]

Answer:

Step-by-step explanation:

the sum of the angles in a triangle is 180

33+2c+c-18=180

3c=180+18-33

3c=165

c=165/3

c=55

7 0
2 years ago
In the inequality 6a+4b>10, what could be the possible value of a if b=2?
Arlecino [84]

We are given the following inequality:

6a+4b>10

If we replace b = 2, we get:

\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}

Now we solve for "a" first by subtracting 8 on both sides:

\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}

Now we divide both sides by 6

\frac{6a}{6}>\frac{2}{6}

Simplifying:

a>\frac{1}{3}

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

3 0
1 year ago
A coin is tossed twice. Let H represents heads, T represents tails, and the combination of the two letters represent the outcome
denis23 [38]

Answer:

{HH, HT, TH, TT}

Step-by-step explanation:

The set of all possible outcomes in tossing a coin twice is;

{HH, HT, TH, TT}

In the first toss the coin may land Heads. In the second toss the coin may land Heads or Tails. This can be represented as;

HH, HT

Heads in the first and second tosses. Heads in the first toss followed by a Tail in the second toss.

In the first toss the coin is also likely to land Tails. In the second toss the coin may land Heads or Tails. This can be represented as;

TH, TT

Tails in the first toss followed by a Head in the second toss. Tails in the first and second tosses.

Combining these two possibilities will give us the set of all possible outcomes in tossing a coin twice is;

{HH, HT, TH, TT}

4 0
3 years ago
Joe is at the ice cream shop, and his house is 10 blocks north of the shop. The park is 10 blocks south of the ice cream shop. W
Furkat [3]

Answer:

The distance between the ice cream shop and Joe's house is the same as the distance between the ice cream shop and the park. So Joe is not closer to the park or his house, he is in the middle.

Step-by-step explanation:

We consider that the ice cream shop is the zero value in the number line. We assume that going north is positive (right side of the number line) and going south is negative (left side of the number line).

The house position is 10 block north of the ice cream shop, so it is represented by the integer 10.

The park is 10 blocks south of the ice cream shop, so it is represented by the integer -10.

The lower absolute value of the integer, the closer position from the ice cream shop.

If we calculate the absollute value of the House position:

|10|=10

Then, we calculate the the absollute value of the Parkposition

|-10|=10

In conclusion, the distance between the ice cream shop and Joe's house is the same as the distance between the ice cream shop and the park. Joe is in the middle.

5 0
2 years ago
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