Solve and graph the absolute value inequality: |2x + 1| ≤ 5. number line with closed dots on -3 and 2 with shading going in the
opposite directions. number line with closed dots on -3 and 2 with shading in between. number line with open dots on -3 and 2 with shading in between. number line with closed dots on -2 and 2 with shading in between.
After solving and graphing the absolute value inequality of
the equation |2x + 1| ≤ 5, I’ve come up with the
conclusion that the answer would be the second option or the number line with
closed dots on -3 and 2 with shading in between. I am hoping that this
answer has satisfied your query about this specific question.
We are given with the inequality |2x + 1| ≤ 5 and asked to solve the equation. In this case, we take first the positive side, that is 2x + 1 ≤ 5. this is equal to 2x ≤ 4 or x ≤ 2. For the negative side, the equality is -5 ≤ 2x + 1. This is equal to -6 ≤ 2x or -3 ≤ x. Hence the solution is -3 ≤ x ≤ 2. The answer is B. closed dots on -3 and 2 with shading in between. The equal in <span>≤ means closed dots.</span>
(five) should match the number of rows of 
(four).