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N76 [4]
2 years ago
9

Consider the following four pairs of molecules. You may use 1H-NMR, 13C-NMR, or IRspectroscopyto differentiate the structures, b

ut you may use a technique only once on this page(i.e. each pair mustuse a different technique).For each pair, pick one of the above forms of spectroscopy and describe the single clearest difference between the two compounds by that analytical technique.

Chemistry
1 answer:
GREYUIT [131]2 years ago
4 0

Answer:

The question is incomplete. The structures were not added to the question. Find attached of the structure and the given answer.

Explanation:

See the attached file for explanation

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This must be your work, otherwise it's against the Brainly code of conduct. If you need help finding a newspaper, go to BBC. They have plenty of relevant articles.

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1 year ago
Can an ionic bond exist in a molecular formula?
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yes

Explanation:

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2 years ago
Which statement is correct abound chemical bonding in BF3 molecule O The molecule is not stable and hardly exist since the numbe
IceJOKER [234]

The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

<h3>Is BF3 molecule stable or not?</h3>

BF3 molecule is a stable molecule because all the electrons present in the outermost shell of boron are covalently bonded with fluorine. Boron in BF3, three bonds is the maximum possible because boron only has 3 electrons to share.

So we can conclude that the molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

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1 year ago
What happens to the kinetic energy of a ball if its velocity is increased to twice its original value?
dem82 [27]

Answer:

idk

Explanation:

4 0
3 years ago
One mole of an ideal gas is contained in a cylinder with a movable piston. The temperature is constant at 77°C. Weights are remo
frozen [14]

Answer:

The total work is 4957.45J

Explanation:

For an ideal gas, at constant temperature the definition of work (W) is

W = - P.dV = - n.R.T \int\limits^i_f {\frac{dV}{V} \\W = - n.R.T. Ln (\frac{V_{f}}{V_{I}})\\W = - n.R.T. Ln (\frac{P_{i}}{P_{f}})

where P is the pressure, V the volume, n the moles number, T the temperature and R the gas constant.

To solve the problem is necessary to replace the two steps in the equation

Stape 1: n  = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 5.50atm and Pf = 2.43atm.

W_{1} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{5.50atm}{2.43atm}) = 23.44atm.Lx101.325\frac{J}{atm.L} =2375.44J

Stape 2: n  = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 2.43atm and Pf = 1.00atm.

W_{2} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{2.43atm}{1.00atm}) = 25.48atm.Lx101.325\frac{J}{atm.L} =2582.01J

The total work is the sum of the two steps

W = W_{1} + W_{2} = 2375.44J + 2582.01J = 4957.45J

4 0
3 years ago
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